Ok using HashSet or TreeSet I know whether particular EmpId is exist
or not. as
TreeSet ts = new TreeSet<String>();
if (ts.add(tokens[5]))
{
//Here it will add this string into TreeSet only if it is not
present. Means now I know whther EmpId is already exist or not in a
list. But I can't determine its index means whether it is in first
location or second or somewhere else. Because If i get location then I
can override older values with new one.
}
On May 25, 2:43 pm, "pramod.deore" <[email protected]> wrote:
> Still I am confused How I will check whether that list contains
> particular EmpId number or not? Means if there is no record for that
> particular empId then I am going to create new row but if it is
> present then I will only update that particulars row's value.
>
> On May 25, 2:27 pm, Daniel Drozdzewski <[email protected]>
> wrote:
>
>
>
> > Pramod,
>
> > you are creating new ArrayList that backs new SimpleAdapter every time
> > you receive an update, hence all there is to display is only what came
> > with the update. Activity should have one Adapter per ListView and
> > both of those should not be re-created, but created once and the
> > updated, when needed.
>
> > Your ListView and Adapter are used wrongly.
>
> > Please read tutorials on both of those.
>
> > On Wed, May 25, 2011 at 9:46 AM, pramod.deore <[email protected]>
> > wrote:
> > > Yes Daniel I will try some sample code side by side but it will be
> > > great if you help to solve this tragidy. Look at my code:
>
> > > private BroadcastReceiver broadcastReceiver = new BroadcastReceiver()
> > > {
> > > @Override
> > > public void onReceive(Context context, Intent intent)
> > > {
> > > String res = intent.getStringExtra("Response");
> > > System.out.println ("***********************************");
> > > System.out.println (res);
>
> > > if (res.length() == 0)
> > > {
> > > //Response has not changed
> > > System.out.println("value is
> > > null.................");
> > > }
>
> > > else
> > > {
> > > String delims = "\\^";
>
> > > tokens = res.split(delims);
>
> > > for (int i=0;i<tokens.length;i++)
> > > {
> > > System.out.println("At "+i+" Value is "+tokens[i]);
> > > }
>
> > > if (tokens[1].equalsIgnoreCase("1"))
>
> > > {
>
> > > //write code for empId is exist already or not? If
> > > exist then
> > > update row else create new row
> > > showList();
>
> > > }
>
> > > else
> > > {
> > > //Don't this record to listview
> > > }
> > > }
>
> > > }
> > > };
>
> > > public void showList()
> > > {
>
> > > ArrayList<HashMap<String, String>> mylist = new
> > > ArrayList<HashMap<String, String>>();
> > > HashMap<String, String> map = new HashMap<String,
> > > String>();
> > > map.put("EmpId", tokens[2]);
> > > map.put("Name", tokens[4]);
> > > map.put("MobNo", tokens[5]);
>
> > > mylist.add(map);
> > > // ...
> > > SimpleAdapter mSchedule = new SimpleAdapter(this,
> > > mylist,
> > > R.layout.listcolumns,
> > > new String[] {"EmpId", "Name",
> > > "MobNo"}, new int[]
> > > {R.id.EmpId, R.id.Name, R.id.MobNo});
> > > list.setAdapter(mSchedule);
> > > }
>
> > > Now using this code listview updated continously but it shows only one
> > > updated record. Means suppose first record is like:
>
> > > EmpId EmpName MobNo City ..... Gender
>
> > > 1 Pramod 789 Nasik M
>
> > > and suppose server send second record then first record is gone and
> > > shows only one record as:
>
> > > EmpId EmpName MobNo City ..... Gender
>
> > > 1 1 Tom 456 NY M
>
> > > On May 25, 1:29 pm, Daniel Drozdzewski <[email protected]>
> > > wrote:
> > >> Pramod,
>
> > >> You have to read up on ListView and some Adapter that backs the
> > >> ListView providing it with data.
>
> > >> When you receive new set of data to be displayed or your data has
> > >> changed, you call BaseAdapter.notifyDataSetChanged() to notify the
> > >> associated ListView to redraw all visible items.
>
> > >> ListView and Adapter are powerful, hence not easy to grasp at the
> > >> beginning, so you have to go through some tutorial first, if you want
> > >> to use them.
>
> > >> On Wed, May 25, 2011 at 9:18 AM, pramod.deore <[email protected]>
> > >> wrote:
> > >> > Hi actually I am getting a string with some delimilater. Now using
> > >> > split() I am split that response. after spliting I am getting string
> > >> > array of size 40. I am not going to display all 40 fields. I will show
> > >> > near about 10 fields.
>
> > >> > Once again let me explain what I want:
>
> > >> > Using socket connection I am receiving response from server. I want to
> > >> > display this response in list. This list contains say 10 columns.
> > >> > Suppose first two records as
>
> > >> > EmpId EmpName MobNo City ..... Gender
>
> > >> > 1 Pramod 789 Nasik M
> > >> > 1 1 Tom 456 NY M
>
> > >> > Now suppose next record again for EmpId 1 then other fields will
> > >> > change and it will be:
>
> > >> > EmpId EmpName MobNo City ..... Gender
>
> > >> > 1 Deore 789 Nasik M
> > >> > 1 1 Tom 456 NY M
>
> > >> > Now suppose server send again some data with EmpId which is not exist
> > >> > above then it must have to add this new record.And it will be
>
> > >> > EmpId EmpName MobNo City ..... Gender
>
> > >> > 1 Deore 789 Nasik M
> > >> > 1 1 Tom 456 NY M
> > >> > 45 Rob 123 XYZ M
>
> > >> > Now how to achieve this?
>
> > >> > On May 25, 12:33 pm, Nikolay Elenkov <[email protected]>
> > >> > wrote:
> > >> >> On Wed, May 25, 2011 at 4:15 PM, pramod.deore
> > >> >> <[email protected]> wrote:
>
> > >> >> > On May 25, 12:08 pm, Nikolay Elenkov <[email protected]>
> > >> >> > wrote:
> > >> >> >> On Wed, May 25, 2011 at 4:01 PM, pramod.deore
> > >> >> >> <[email protected]> wrote:
> > >> >> >> > Hi Ravi thanks for reply. actually it will becomes more
> > >> >> >> > complicated.
> > >> >> >> > Because server is sending data 2-3 times within a second And it
> > >> >> >> > will
> > >> >> >> > not be good idea to store data such a frequently.
>
> > >> >> >> > Can somebody please provide me a guideline How I can check
> > >> >> >> > whether
> > >> >> >> > some key (here Name ) is already exist in listview?
>
> > >> >> >> If you don't have much data to deal with it, it might be easier to
> > >> >> >> just replace everything and re-display. It doesn't really matter
> > >> >> >> what exactly changed.
>
> > >> >> > Actually I am dealing with huge data. In above code just show a
> > >> >> > sample
> > >> >> > of three fields but there are more than 40 fields.
>
> > >> >> Why is top-posting the norm on this list? Please write your reply
> > >> >> *below*
> > >> >> the previous one, so it reads like a conversation. Trimming also
> > >> >> helps.
>
> > >> >> How are you going to display 40 fields in a ListView? It doesn't
> > >> >> really matter
> > >> >> though, you usually care if a particular row/record changed and
> > >> >> update/replace
> > >> >> the whole record in your model/adapter. If you want to be able
> > >> >> replace a
> > >> >> particular record, use some key (e.g., the employee ID) to search for
> > >> >> it,
> > >> >> and update/replace it.- Hide quoted text -
>
> > >> >> - Show quoted text -
>
> > >> > --
> > >> > You received this message because you are subscribed to the Google
> > >> > Groups "Android Developers" group.
> > >> > To post to this group, send email to
> > >> > [email protected]
> > >> > To unsubscribe from this group, send email to
> > >> > [email protected]
> > >> > For more options, visit this group at
> > >> >http://groups.google.com/group/android-developers?hl=en
>
> > >> --
> > >> Daniel Drozdzewski- Hide quoted text -
>
> > >> - Show quoted text -
>
> > > --
> > > You received this message because you are subscribed to the Google
> > > Groups "Android Developers" group.
> > > To post to this group, send email to [email protected]
> > > To unsubscribe from this group, send email to
> > > [email protected]
> > > For more options, visit this group at
> > >http://groups.google.com/group/android-developers?hl=en
>
> > --
> > Daniel Drozdzewski- Hide quoted text -
>
> > - Show quoted text -- Hide quoted text -
>
> - Show quoted text -
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