Hi, You should use DocumentBuilderFactory, DocumentBuilder and Document classes.
Here you have an example. URL url = new URL("http://..."); HttpURLConnection urlConnection = (HttpURLConnection) url.openConnection(); urlConnection.connect(); DocumentBuilderFactory dbf = DocumentBuilderFactory.newInstance(); DocumentBuilder db = dbf.newDocumentBuilder(); Document doc = db.parse(urlConnection.getInputStream()); doc.getDocumentElement().normalize(); NodeList nodeLst = doc.getElementsByTagName("categories"); for (int i = 0; i < nodeLst.getLength(); i++) { Node currentNode = nodeLst.item(i); ... } You should do it in an AsyncTask or Runnable. Regards, On Aug 1, 9:29 am, Hari <hariluv...@gmail.com> wrote: > Plz, Anyone can please help me with parsing an XML String in > Android??? > > Here is the Xml file which has to be accepted as a string and display > the contents of this xml code?? > > <?xml version='1.0' encoding='iso-8859-1'?> > <categories> > <category id="1"> > <name>Real Estate</name> > </category> > <category id="2"> > <name>Hospitals</name> > </category> > <category id="3"> > <name>Gifts</name> > </category> > <category id="4"> > <name>Domestic Help</name> > </category> > </categories> > > Plz help me out.. > I'm extremely new to ANdroid development... -- You received this message because you are subscribed to the Google Groups "Android Developers" group. To post to this group, send email to android-developers@googlegroups.com To unsubscribe from this group, send email to android-developers+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/android-developers?hl=en