This code might help you..
public void onCreate(Bundle savedInstanceState)
{
super.onCreate(savedInstanceState);
setContentView(R.layout.search);
Button b2=(Button)findViewById(R.id.button1);
b2.setOnClickListener(new View.OnClickListener() {
public void onClick(View v) {
Intent intent=new Intent(v.getContext(),MainPage.class);
startActivity(intent);
}});
in another class:
Button b=(Button)findViewById(R.id.Button);
b.setOnClickListener(new View.OnClickListener() {
public void onClick(View v) {
Intent intent=new
Intent(v.getContext(),Search.class);
startActivityForResult(intent,0);
} });
}
On Aug 2, 8:15 pm, Shabu Thomas <[email protected]> wrote:
> In my application, activity A is the default one and I have created
> another activity B. There is a button in each activity. On click event
> of the button, the other activity should be brought to front. So, for
> the first click, the activity will be created (OnCreate will be
> called) and for the subsequent clicks, new instances should not be
> created but it should be brought to front only (OnNewIntent should be
> called).
>
> Button click of Activity B will do the same. But, when we click the
> button on A, instead of calling OnNewIntent of B, OnCreate will be
> called which means B will again be created. How can we avoid it?
>
> public void OnMyButtonClickOfA(View view)
> {
> Intent i = new Intent(this, B.class);
> i.setFlags(Intent.FLAG_ACTIVITY_CLEAR_TOP |
> Intent.FLAG_ACTIVITY_SINGLE_TOP ); // What should I do here in order
> to avoid the recreation of B?
>
> i.putExtra("string", "Again Called");
> startActivity(i);
>
> }
>
> public void OnMyButtonClickOfB(View view)
> {
> Intent intent = new Intent(this, A.class);
> intent.setFlags(Intent.FLAG_ACTIVITY_CLEAR_TOP |
> Intent.FLAG_ACTIVITY_SINGLE_TOP );
> //intent.putExtra("MyClass", m);
> intent.putExtra("string", "Recalled");
> startActivity(intent);
>
> }
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