createPackageContext takes a String as the first parameter, so it shoud be
createPackageContext("your.package.name.here"...). Note the double quotes.Don't think you need the "ignore security" flag in this case, just to load the resources. -- Kostya 3 декабря 2011 г. 22:45 пользователь Matt Clark <[email protected]>написал: > I have no idea how to set that up, I found an example that would use: > > Context r = > > Context.createPackageContext(tinyClark.android.libraries.LanguagePack,Context.CONTEXT_IGNORE_SECURITY); > > But i get an error that tinyClark.android.libraries.LanguagePack > cannot be resolved to a variable, and when i try to fix it it creates > a new class in tinyClark.android.* > > -- > You received this message because you are subscribed to the Google > Groups "Android Developers" group. > To post to this group, send email to [email protected] > To unsubscribe from this group, send email to > [email protected] > For more options, visit this group at > http://groups.google.com/group/android-developers?hl=en > -- You received this message because you are subscribed to the Google Groups "Android Developers" group. To post to this group, send email to [email protected] To unsubscribe from this group, send email to [email protected] For more options, visit this group at http://groups.google.com/group/android-developers?hl=en
