I guess
Show of ListView rather than wrong, You have failed to parse JSON.

> ArrayAdapter<String> adapter = new
> ArrayAdapter<String>(this,android.R.layout.simple_list_item_1,
> android.R.id.text1,str1);
> lv.setAdapter(adapter);
this code is correct.

Structure of the JSON is?

2012/8/4 Meena Rengarajan <[email protected]>:
> How should i use Array adapter here to get listview values .. I am very new
> to Android can anyone help me please..
>
> I used this in my code,
>
> ArrayAdapter<String> adapter = new
> ArrayAdapter<String>(this,android.R.layout.simple_list_item_1,
> android.R.id.text1,str1);
> lv.setAdapter(adapter);
>
> On Sat, Aug 4, 2012 at 12:47 PM, Meena Rengarajan <[email protected]>
> wrote:
>>
>> How do i wanna split a string into two parts here by omitting first
>> character ?
>>
>>
>> On Saturday, August 4, 2012 10:36:18 AM UTC+5:30, Meena Rengarajan wrote:
>>>
>>> This is my code. Listview using Json in Android . But my lists is not
>>> displaying when i click a button.. Only displaying first activity alone.
>>> Whats wrong here ? can anyone help me ..
>>> try {
>>>      JSONObject json1=new JSONObject(resultJSON);
>>>      JSONArray jsonArray=json1.getJSONArray("");
>>>      int length = jsonArray.length();
>>>      System.out.println("json1:"+json1);
>>>      System.out.println("jsonarray:"+jsonArray);
>>>      String[] str1 = new String[length];
>>>      for (int i = 0; i < str1.length; i++) {
>>>
>>> str1[i]=jsonArray.getJSONObject(i).getJSONObject("FORM").getJSONArray("FPROP".getJSONObject(0).getString("FNAME");
>>>
>>> }
>>> } catch (Exception e) {
>>> // TODO: handle exception
>>> Toast.makeText(NewActivity.this,"sorry", Toast.LENGTH_LONG).show();
>>> }
>>>  ArrayAdapter<String> adapter = new
>>> ArrayAdapter<String>(this,android.R.layout.simple_list_item_1,
>>> android.R.id.text1,str1);
>>>
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