Lew wrote:
> Foo results = new Foo [tasks.length] [priorities.length];
> for (int tx = 0; tx < tasks.length; ++tx)
> {
> for (int px = 0; ix < priorities.length; ++px)
> {
> Task task = tasks[tx];
> Priority priority = priorities[px];
> results [px][tx] = whatDoYouWantHerePleaseTellUs(task, priority);
>
Oops. '[tx][px]' . I got it backwards.
}
> }
>
> You need to tell us what you want in that box.
>
> Obviously it's a value that depends on the two indexing values. You likely
> would want to factor
> that out as a method on the two arguments as I showed here.
>
> So what do you want in that box?
>
> --
> Lew
>
>
>
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