you use equals() method for string comparison. Because java supports this
method for strings...
Try this:
EditText editText1 = (EditText) findViewById(R.id.editText1);
String userName = editText1.getText().toString().trim();
EditText editText2 = (EditText) findViewById(R.id.editText2);
String password = editText2.getText().toString().trim();
if(userName.equals(userName1) || password.equals(password1)){
startActivity(intent);
}
else{
Context context = getApplicationContext();
CharSequence text = "Incorrect Username or Password!";
int duration = Toast.LENGTH_SHORT;
Toast toast = Toast.makeText(context, text, duration);
toast.show();
}
Regards
Android developer
Trinay Technology Solutions
www.trinaytech.com
5705750475
On Monday, February 4, 2013 1:50:02 AM UTC+5:30, [email protected]
wrote:
>
> I am trying to create a login screen for your basic hello world program. I
> do not need a database for this so I hard coded the username and password
> directly into the code. The problem I am having is when I enter the correct
> username and password, I get my error message stating that either one is
> wrong. Here is the code I have, any help would be greatly appreciated.
>
> public void welcomeScreen(View view){
> String userName1 = "student";
> String password1 = "school";
> Intent intent = new Intent(this, WelcomeScreen.class);
> EditText editText1 = (EditText) findViewById(R.id.editText1);
> String userName = editText1.getText().toString();
>
> EditText editText2 = (EditText) findViewById(R.id.editText2);
> String password = editText2.getText().toString();
>
> if(userName != userName1 || password != password1){
> Context context = getApplicationContext();
> CharSequence text = "Incorrect Username or Password!";
> int duration = Toast.LENGTH_SHORT;
>
> Toast toast = Toast.makeText(context, text, duration);
> toast.show();
> }
>
> else startActivity(intent);
> }
>
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