if you mean using webservice to send request and receive a response.
then you could you use this code, you could you DOM or SAX parser to parse
the respone but to send a request.
import java.util.List;
import org.apache.commons.lang.StringEscapeUtils;
import org.ksoap2.SoapEnvelope;
import org.ksoap2.serialization.PropertyInfo;
import org.ksoap2.serialization.SoapObject;
import org.ksoap2.serialization.SoapSerializationEnvelope;
import org.ksoap2.transport.HttpTransportSE;
import android.util.Log;
import android.util.Xml;
public class DataFetcher {
private static final String NAMESPACE ="";
private static String URL =
"";
private static final String METHOD_NAME = "";
private static final String SOAP_ACTION = "";
private HttpTransportSE androidHttpTransport;
private final SoapSerializationEnvelope envelope;
public DataFetcher(int id)
{
SoapObject request = new SoapObject(NAMESPACE, METHOD_NAME);
PropertyInfo propInfo = new PropertyInfo();
propInfo.name = "Channel";
propInfo.type = PropertyInfo.INTEGER_CLASS;
request.addProperty(propInfo, id);
/* PropertyInfo propInfo3 = new PropertyInfo();
propInfo3.name = "limit";
propInfo3.type = PropertyInfo.INTEGER_CLASS;
request.addProperty(propInfo3, 2);*/
PropertyInfo propInfo2 = new PropertyInfo();
propInfo2.name = "Key";
propInfo2.type = PropertyInfo.STRING_CLASS;
request.addProperty(propInfo2, "2724466");
envelope =
new SoapSerializationEnvelope(SoapEnvelope.VER10);
envelope.dotNet = true;
envelope.encodingStyle = SoapSerializationEnvelope.XSD;
envelope.setOutputSoapObject(request);
androidHttpTransport =
new HttpTransportSE(URL);
androidHttpTransport.debug=true;
Fetchdata();
}
public List<Channel> Fetchdata()
{
DataParser chanParser = new DataParser (); // SAX Parser - developed by me
try
{
androidHttpTransport.call(SOAP_ACTION, envelope);
String xml= androidHttpTransport.responseDump.toString();
String strUnEscapeHTML = StringEscapeUtils.unescapeHtml(xml);
Xml.parse(strUnEscapeHTML, chanParser);
}
catch(Exception e)
{
Log.e("SAX-Parser", "Exception = >" + e.toString());
}
return chanParser.getChannels();
}
}
2013/5/22 Ibrahim Sada <[email protected]>
> Hi Friends..
> how to sends and receive xml file from android to server and vise versa
> Thanks in Advance..
>
>
>
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