Java built-in serialization has many benefits, but for efficiency you may want to consider something else, such as protobuf.
Yusuf Saib Android ·T· · ·Mobile· stick together The views, opinions and statements in this email are those of the author solely in their individual capacity, and do not necessarily represent those of T-Mobile USA, Inc. On Oct 13, 12:41 pm, Dan Sherman <[email protected]> wrote: > Not sure as to an answer to your question (I'm not that familiar with the > internals), however, as a work-around you could probably do something like: > > MyObject arr[] = new MyObject[list.size()]; > serialize(arr); > send(arr); > > ----- > recv(arr) > list.addAll(arr); > > Obviously abbreviated, and doesn't quite answer the question, but there's > definitely ways to get the data from A to B differently... > > - Dan > > > > On Tue, Oct 13, 2009 at 3:32 PM, dsukhram <[email protected]> wrote: > > > I can return an ArrayList of Strings just not an ArrayList of my Stop > > object. And since this whole process works fine when I take android > > out of the equation..this leads me to believe that serialization is > > handled slightly differently in android. Anybody? > > > On Oct 12, 6:28 pm, dsukhram <[email protected]> wrote: > > > I am writing an android client app which sends a Hashtable to a remote > > > servlet and recieves an ArrayList consisting of a custom Object which > > > is serializable. This ran fine when I was just receiving the > > > ArrayList from a java console app. So I know my objects are being > > > serialized and deserialized properly. But when I port the same client > > > code over to android I get an error when trying to read the ArrayList > > > of my objects that is sent back from the servlet. > > > > Is there any differences in the way Android does serialization? I > > > can't seem to find any documentation that says it does. The error I > > > receive is: > > > > java.lang.IndexOutOfBoundsException: Invalid location > > > > at java.util.ArrayList.get(ArrayList.java:350) > > > > ============ My Android Client app is as > > > follows================================= > > > > public class TTCPointService { > > > private Logger logger; > > > private FileHandler handler; > > > > public TTCPointService(){ > > > > try > > > { > > > logger = > > Logger.getLogger(TTCPointService.class.getName()); > > > handler = new FileHandler("ttcservice.log"); > > > handler.setFormatter(new SimpleFormatter()); > > > logger.addHandler(handler); > > > } > > > catch(IOException e) > > > { > > > logger.log(Level.SEVERE,e.toString()); > > > } > > > } > > > > public ArrayList<Stop> ConnectToServlet() > > > { > > > ArrayList<Stop> list = new ArrayList<Stop>(); > > > > Hashtable<String, String>obj = new Hashtable<String,String>(); > > > obj.put("lat", "12.00"); > > > obj.put("log", "-23.00"); > > > > try > > > { > > > URL servletURL = new URL("http://192.168.0.69:8080/ > > > GTFSProcessor/TTCPoints"); > > > HttpURLConnection servletConnection = (HttpURLConnection) > > > servletURL.openConnection(); > > > servletConnection.setDoOutput(true); > > > servletConnection.setDoInput(true); > > > servletConnection.setUseCaches(false); > > > servletConnection.setDefaultUseCaches(false); > > > > servletConnection.setRequestProperty("Content- > > > type","application/x-java-serialized-object"); > > > servletConnection.setRequestMethod("POST"); > > > logger.log(Level.INFO,"Connecting to Servlet"); > > > > //Send object to servlet > > > OutputStream os = servletConnection.getOutputStream(); > > > ObjectOutputStream oos = new ObjectOutputStream(os); > > > oos.writeObject(obj); > > > > oos.flush(); > > > oos.close(); > > > logger.log(Level.INFO,"Hashtable sent to Servlet"); > > > > //Read from servlet > > > InputStream is = servletConnection.getInputStream(); > > > ObjectInputStream ois = new ObjectInputStream(is); > > > > list = (ArrayList<Stop>)ois.readObject(); > > > logger.log(Level.INFO,"Reading Object from Servlet"); > > > > os.close(); > > > > } > > > catch(IOException e) > > > { > > > logger.log(Level.SEVERE,e.toString()); > > > } > > > catch(ClassNotFoundException e) > > > { > > > logger.log(Level.SEVERE,e.toString()); > > > } > > > return(list); > > > } > > > > } > > > > =============The code that raises the error > > > is=================================== > > > > ArrayList<Stop> list = new ArrayList<Stop>(); > > > TTCPointService service = new TTCPointService(); > > > list = (ArrayList<Stop>)service.ConnectToServlet(); > > > > Toast.makeText(mapView.getContext(), "list contains: > > > "+list.get(0).getName(), Toast.LENGTH_SHORT).show(); --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "Android Developers" group. To post to this group, send email to [email protected] To unsubscribe from this group, send email to [email protected] For more options, visit this group at http://groups.google.com/group/android-developers?hl=en -~----------~----~----~----~------~----~------~--~---
