On Nov 17, 7:06 am, Streets Of Boston <flyingdutc...@gmail.com> wrote:
> When using openInputStream on the content-resolver, the returned input-
> stream is not as 'flexible' as a FileInputStream. For example,
> FileInputStreams can be retried if something goes wrong. The one
> returned by openInputStream can not.
What is an example of "something going wrong"? Are there Exceptions
you would catch and ignore while reading a FileInputStream?
>
> Togetthe fully qualifiedpath-name to the image-file(jpg/png),
> query theUriof the image and obtain the value of the DATA ("_data")
> column. This value is a String, the fully-qualifiedpathto the imagefile. Then
> you can create a FileInputStream from thisfile.
>
> On Nov 17, 4:08 am, MrChaz <mrchazmob...@googlemail.com> wrote:
>
> > If I remember rightly, the gallery returns you a contenturi
> > so you'll want to do something like: getContentResolver
> > ().openInputStream(uri)
>
> > On Nov 17, 5:53 am, Abhi <abhishek.r.sha...@gmail.com> wrote:
>
> > > Hi Dianne,
>
> > > I am trying to do the following.
>
> > > I have an Image viewer where in the user picks an Image from within
> > > the gallery. Theurito that selected Image is available to me. Now, I
> > > want to use thisURIinformation and send it as afileover a socket
> > > using FileInputStream. Is this a valid syntax to perform the above
> > > action?
>
> > > FileInputStream fis = new FileInputStream(uri.getPath()); //
> > > Hereuriis theURIof the selected Image
> > > byte[] buffer = new byte[fis.available()];
> > > fis.read(buffer);
>
> > > ObjectOutputStream oos = new ObjectOutputStream
> > > (socket.getOutputStream());
> > > oos.writeObject(buffer);
>
> > > Please help me to move forward.
>
> > > Thanks,
>
> > > Abhi- Hide quoted text -
>
> > - Show quoted text -
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