Anybody figured this out yet ? I need same thing..

On Nov 16, 5:44 pm, Matthew Wardrop <mister.ward...@gmail.com> wrote:
> I too would like to know this.
>
> On Oct 23, 1:31 pm, junker37 <junke...@gmail.com> wrote:
>
>
>
> > I am wondering how to do this as well.  Also, I can't seem to find
> > where this is documented.
>
> > On Oct 19, 4:19 am, Viktor Bresan <viktor.bre...@gmail.com> wrote:
>
> > > Hi all.
>
> > > I would like to have ashapethat hasborderonly on 3 sides: top,
> > > left and right, i.e. I want bottom to beopen.  How can I achieve that
> > > definingshapeinXML?
>
> > > Currently I have a normal 4 sideborderusing the followingshapeXML
> > > definition:
>
> > > <?xmlversion="1.0" encoding="utf-8"?>
> > > <shapexmlns:android="http://schemas.android.com/apk/res/android";
> > >     android:layout_width="fill_parent"
> > >     android:layout_height="fill_parent"
> > >         >
>
> > >         <solid android:color="#FFE8F0F8"
> > >                    />
>
> > >     <strokeandroid:width="1dp"
> > >                 android:color="#808480"
> > >                 />
>
> > >     <padding android:left="1dp"
> > >                  android:top="1dp"
> > >              android:right="1dp"
> > >              android:bottom="1dp"
> > >              />
> > > </shape>
>
> > > Many thanks, Viktor.

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