Business Talk wrote:
> How is it that I can open a file with
>
> FileInputStream inputStream = _Context.openFileInput("songs.zip");
>
>
> but not with
>
> ZipFile zipFile = new ZipFile("songs.zip");
>
> the ZipFile throws the FileNotFoundException. What am I missing?
openFileInput() knows about /data/data/your.package.here/files.
ZipFile(), and everything else in stock Java, does not. You will need to
fully-qualify your path:
ZipFile zipFile=new ZipFile(new File(getFilesDir(), "songs.zip"));
--
Mark Murphy (a Commons Guy)
http://commonsware.com | http://twitter.com/commonsguy
_Beginning Android_ from Apress Now Available!
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