Hello,
When I use SoapEnvelope.VER11, it works fine, But when I use
SoapEnvelope.VER12, it gives me error:
"org.xmlpull.v1.XmlPullParserException: expected: START_TAG".
This is my code...
import java.io.IOException;
import org.ksoap2.SoapEnvelope;
import org.ksoap2.serialization.SoapObject;
import org.ksoap2.serialization.SoapSerializationEnvelope;
import org.ksoap2.transport.HttpTransportSE;
import org.xmlpull.v1.XmlPullParserException;
import android.os.Bundle;
import android.util.Log;
import android.widget.TextView;
public class MyWebService extends Activity {
private static final String SOAP_ACTION = "http://your_URL/
your_mathod_name";
private static final String METHOD_NAME = "your_mathod_name";
private static final String NAMESPACE = "http://your_URL/";;
private static final String URL = "http://your_URL/WebService.asmx?
WSDL";
private Object resultRequestSOAP = null;
String data = "some data";
/** Called when the activity is first created. */
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
TextView tv = new TextView(this);
setContentView(tv);
try {
SoapObject request = new SoapObject(NAMESPACE,
METHOD_NAME);
SoapSerializationEnvelope envelope = new
SoapSerializationEnvelope(SoapEnvelope.VER12);
envelope.encodingStyle =
SoapSerializationEnvelope.ENC2001;
envelope.dotNet = true;
envelope.setOutputSoapObject(request);
request.addProperty(METHOD_NAME, data);
envelope.bodyOut = request;
SoapObject response = null;
HttpTransportSE androidHttpTransport = new
HttpTransportSE(URL);
androidHttpTransport.call(SOAP_ACTION, envelope);
// get the data
response = (SoapObject) envelope.bodyIn;
} catch (IOException e) {
// TODO Auto-generated catch block
e.printStackTrace();
} catch (XmlPullParserException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
}
}
Can u tell me why is this happening with SOAP1.2 ?
Do I need to specify some encoding style for SOAP1.2 ?
Regards,
Pankaj.
On Feb 4, 10:40 am, Kevin Duffey <[email protected]> wrote:
> Like the others said.. it sounds like a starting element is not being found
> before either some text or an end tag. Usually you'll see that error with
> something like:
>
> <node1>
> </node2>
> <node3>
> </node3>
> </node1>
>
> Or
>
> <node1>
> </node1>
> some text
> <node2>
> </node2>
>
> It ALSO depends on how you are moving thru the xml parser.. if you are using
> parser.next() you are moving one parsing element at a time, which means
> you'll find every possible element including text, tags,white space, etc. If
> you use parser.nextTag() you may skip over that 2nd example text issue and
> find node2 start tag.
>
>
>
> On Wed, Feb 3, 2010 at 2:29 PM, Nicholas Albion <[email protected]> wrote:
> > If you determine that the problem is that the XML (or HTML!) is badly
> > formatted and you have no control over it, you can do something like:
>
> > int n;
> > while( (n = xpp.getNext()) != END_DOCUMENT ) {
> > try {
> > // do your parsing element-by-element
> > } catch( org.xmlpull.v1.XmlPullParserException e ) {} // ignore the
> > exception
> > } catch( Throwable e ) {
> > log.warning("error while parsing file: " + e.getMessage(); //
> > you may want to catch any other exceptions and do something about them
> > }
> > }
>
> > It might not be the most efficient practice to perform the try/catch
> > within the loop, but if somebody else is sending you dodgy XML there
> > might not be anything you can do.
>
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