As Mike says, it seems something is missing from your description. From what you said in your response earlier, you are being redirected. However, because you are making the first request, the only way you could be redirected is if the response you got back was a 301 with a Location header filled out. THEN, you make a second request using the Location URL that is returned. If you're getting a 404, as Mike said, the initial URL you're requesting is not being found. I am guessing you are not showing your complete code, or being completely descriptive because well, you don't want to give away your secret sauce.. which I can understand. But something is missing from this that is not allowing us to help you further.
On Wed, Apr 7, 2010 at 7:15 AM, mike <[email protected]> wrote: > On 04/07/2010 03:56 AM, jw wrote: > >> Well, I'm able to set the response url in the "web service", but it's >> the parameters I'm interested in... For now I've just set the response >> URL to www.google.com and the web service adds my parameter which >> gives www.google.com/?x=1&y=2... Since this page is not available, I >> get the 404 status code, not 3xx... >> >> > > Er, um, 404 says that it's not there and that it doesn't know > where it might be, so it's no surprise there's not a Location: > header. > > I suspect that you're not describing the entire process > adequately for us to figure out what's going on. There is > no such thing as a "response url" and a "web service" isn't > especially well defined. Putting these things in terms of what > HTTP 1.1 the protocol does would make it easier. > > Mike, you're not conflating xml/json in the content by any chance? > > > Any help? >> >> /J >> >> On Apr 7, 11:41 am, mike<[email protected]> wrote: >> >> >>> On 04/07/2010 02:30 AM, jw wrote: >>> >>> >>> >>>> Hi, thanks for the idea, but it didn't help. >>>> >>>> >>> >>> >>>> response.getHeaders("Location")[0] gives me null. I've also tried to >>>> print all header keys and vaules, and none of them are Location. >>>> >>>> >>> Are you sure you're actually getting a 3xx code back from the >>> http response? A 301 without a Location header would be bogus. >>> >>> You might try using a network sniffer like ethereal to see the >>> actual network traffic going by too. >>> >>> Mike >>> >>> >>> >>>> Any other ideas? >>>> >>>> >>> >>> >>>> /J >>>> >>>> >>> >>> >>>> On Apr 7, 11:12 am, mike<[email protected]> wrote: >>>> >>>> >>> >>> >>>> On 04/07/2010 12:40 AM, jw wrote: >>>>> >>>>> >>>> >>> >>>> Hi all, >>>>>> >>>>>> >>>>> >>> >>>> thanks for your time and sorry that I wasn't clear enough. >>>>>> >>>>>> >>>>> >>> >>>> I'm making a http post request to a web page which redirects me to >>>>>> different urls depending on the accuracy of my parameters sent in the >>>>>> request. This means that if I do it correct, I'll get redirected to >>>>>> for examplewww.google.comwitha querystring that I need to get >>>>>> (www.google.com?x=1y=2). Maybe that's not the response url, but I >>>>>> don't now how to describe it. It's not the same as the request url >>>>>> anyway. >>>>>> >>>>>> >>>>> >>> >>>> I'm able to get the response status code from the repsonse object, >>>>>> which is ok, and I'm also able to get the html (content) of the >>>>>> response. I just need to know what url I was redirected to. Does this >>>>>> help you? I'm very thankful for all help >>>>>> >>>>>> >>>>> >>> >>>> sounds like you want to use HttpResponse.getHeaders("Location") >>>>> >>>>> >>>> >>> >>>> Mike, it returns an array, but there should only be one if it redirected >>>>> >>>>> >>>> >>> >>>> /J >>>>>> >>>>>> >>>>> >>> >>>> On Apr 7, 5:31 am, Kevin Duffey<[email protected]> wrote: >>>>>> >>>>>> >>>>> >>> >>>> There isn't a response URL that is any different than the request URL. >>>>>>> It's >>>>>>> not as if the server appends a bunch of stuff to the URL you submit >>>>>>> the >>>>>>> request to unless it redirects/forwards to another URL.. in this >>>>>>> case, the >>>>>>> server would append to the URL you requested, redirecting you... but >>>>>>> even if >>>>>>> it did this, your response would indicate a 3xx redirect and the >>>>>>> Location >>>>>>> header, as Frank says above, would contain the new URL you should go >>>>>>> to. If >>>>>>> you did get a 301/2 back, you'd have to actually make another request >>>>>>> yourself. >>>>>>> >>>>>>> >>>>>> >>> >>>> So not sure as the other guys say, what URL you are talking about >>>>>>> >>>>>>> >>>>>> >>> >>>> On Tue, Apr 6, 2010 at 7:59 PM, Frank Weiss<[email protected]> >>>>>>> wrote: >>>>>>> >>>>>>> >>>>>> >>> >>>> I don't know what "response URL" means. The only URLs in an HTTP >>>>>>>> response >>>>>>>> that come to mind are: 1) the "Location" response header for a >>>>>>>> 301/302 >>>>>>>> status code, 2) some string in the response data (such as an HTML >>>>>>>> anchor >>>>>>>> element) that you want to interpret as a URL. >>>>>>>> >>>>>>>> >>>>>>> >>> >>>> On Tue, Apr 6, 2010 at 1:59 PM, jw<[email protected]> wrote: >>>>>>>> >>>>>>>> >>>>>>> >>> >>>> Hi all, >>>>>>>>> >>>>>>>>> >>>>>>>> >>> >>>> I have a problem. I'm doing a http post request to a URL like this; >>>>>>>>> >>>>>>>>> >>>>>>>> >>> >>>> DefaultHttpClient httpclient = new DefaultHttpClient(); >>>>>>>>> HttpPost httppost = new HttpPost(url); >>>>>>>>> HttpResponse response = httpclient.execute(httppost); >>>>>>>>> >>>>>>>>> >>>>>>>> >>> >>>> I am able to get the response content (html in this case) but I would >>>>>>>>> like to be able to get the url of the response. Is there a way? Or >>>>>>>>> could i use some other technique to do the post request and >>>>>>>>> retrieve >>>>>>>>> the url? >>>>>>>>> >>>>>>>>> >>>>>>>> >>> >>>> The repsonse url is lkewww.url.com?x=1&y=2<http://www.url.com/?x=1&y=2>and >>>>>>>>> would like to get the >>>>>>>>> parameter values, I've tried to use the getParams().getParameter() >>>>>>>>> on >>>>>>>>> the HttpResponse object without any success. So if anyone has a >>>>>>>>> solution to get the parameters without getting the url, that's ok >>>>>>>>> :) >>>>>>>>> >>>>>>>>> >>>>>>>> >>> >>>> Thanks in advance. >>>>>>>>> >>>>>>>>> >>>>>>>> >>> >>>> /J >>>>>>>>> >>>>>>>>> >>>>>>>> >>> >>>> -- >>>>>>>>> You received this message because you are subscribed to the Google >>>>>>>>> Groups "Android Developers" group. >>>>>>>>> To post to this group, send email to >>>>>>>>> [email protected] >>>>>>>>> To unsubscribe from this group, send email to >>>>>>>>> [email protected]<android-developers%[email protected]> >>>>>>>>> <android-developers%[email protected]<android-developers%[email protected]> >>>>>>>>> > >>>>>>>>> For more options, visit this group at >>>>>>>>> http://groups.google.com/group/android-developers?hl=en >>>>>>>>> >>>>>>>>> >>>>>>>> >>> >>>> To unsubscribe, reply using "remove me" as the subject. >>>>>>>>> >>>>>>>>> >>>>>>>> >>> >>>> -- >>>>>>>> You received this message because you are subscribed to the Google >>>>>>>> Groups "Android Developers" group. >>>>>>>> To post to this group, send email to >>>>>>>> [email protected] >>>>>>>> To unsubscribe from this group, send email to >>>>>>>> [email protected]<android-developers%[email protected]> >>>>>>>> <android-developers%[email protected]<android-developers%[email protected]> >>>>>>>> > >>>>>>>> For more options, visit this group at >>>>>>>> http://groups.google.com/group/android-developers?hl=en >>>>>>>> >>>>>>>> >>>>>>> >> > > -- > You received this message because you are subscribed to the Google > Groups "Android Developers" group. > To post to this group, send email to [email protected] > To unsubscribe from this group, send email to > [email protected]<android-developers%[email protected]> > For more options, visit this group at > http://groups.google.com/group/android-developers?hl=en > -- You received this message because you are subscribed to the Google Groups "Android Developers" group. 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