Any alternate way to do this will also help me. Thanks, Sachin
On Friday, June 13, 2014 8:00:44 PM UTC+5:30, Sachin Singh Senger wrote: > Hi, > > I am having drag and drop scenario. > I am maintaining the dropped components in an array, when I drop an > element I add them in that array. > What I am doing is I use ng-repeat to append the element in the UI as > well. > > Somehow I created a directive which allows the elements to show randomly > wherever I drop them (not in a sequence as ng-repeat does). > So in background I always have all the properties by ng-repeat so that I > can get all the properties of the dropped component and show those in > another panel. > > ISSUE: Now if I go to another view and again I come back to my drag and > drop view the ng-repeat re arranges the elements. All the elements > rearrange in a line as ng-repeat re-runs. > (I am already using factory for maintaining the data so I don't loose any > data e.g. array and other changed properties) > > My query, Is there any way so that I can get the same UI of a view as I > left when going to another view? > > Thanks, > Sachin > -- You received this message because you are subscribed to the Google Groups "AngularJS" group. To unsubscribe from this group and stop receiving emails from it, send an email to [email protected]. To post to this group, send email to [email protected]. Visit this group at http://groups.google.com/group/angular. For more options, visit https://groups.google.com/d/optout.
