Hey guys, I have a project with heavy promises use where sometimes I use
$timeout to get set a timer for my calls (this is pseudocode just for the
example, please don't focus on it)
firstPromise([
$http.get('/foo/bar'),
$timeout(angular.noop, 1500),
]).then(function() {
// ...
});
I saw in documentation $timeout arguments are optional but if I pass no
function when timer arrives I get "TypeError: fn is not a function".
> $timeout(1000)
> < Promise {$$state: Object, $$timeoutId: 187}
> app-bootstrap.js:16 TypeError: fn is not a function
> at angular.js:16299
> at completeOutstandingRequest (angular.js:4924)
> at angular.js:5312(anonymous function) @ app-bootstrap.js:16(anonymous
> function) @ angular.js:16302completeOutstandingRequest @
> angular.js:4924(anonymous function) @ angular.js:5312
>
> > $timeout()
> < Promise {$$state: Object, $$timeoutId: 188}
> app-bootstrap.js:16 TypeError: fn is not a function
> at angular.js:16299
> at completeOutstandingRequest (angular.js:4924)
> at angular.js:5312
My question is: as $timeout returns a promise can we use argument type
detection to use angular.noop if first argument is a number?
$timeout(10000); // equals to $timeout(angular.noop, 1000)
Which will allow us to chain this promise with others in a more readable
way.
What do you think?
--
You received this message because you are subscribed to the Google Groups
"AngularJS" group.
To unsubscribe from this group and stop receiving emails from it, send an email
to [email protected].
To post to this group, send email to [email protected].
Visit this group at http://groups.google.com/group/angular.
For more options, visit https://groups.google.com/d/optout.
