Thanks this worked great.
I really appreciate the time you have taken to help.
On Tuesday, 21 February 2017 05:44:40 UTC, Sander Elias wrote:
>
> Hi,
>
> You should return it inside a promise, and then use it inside a .then at
> the place you need it. (no need for $q. and using deffered's is usually
> considered an antipattern!)
>
> function checkNikeUrl(url, size, inventoryData) {
> return $http.get(url).then(function(response) {
>
> var url = 'http://www.nike.co.uk/search?q=' + code;
> return checkNikeUrl(url, size, inventoryData);
>
>
> if(store === 'nike') {
> return checkNike(store, code, size);
> //$log.debug(inventoryData);
> //return inventoryData;
> }
>
> Then, where you need it:
> checkInventory()
> .then(function(inventoryData){
> // do something with the data. most of the time it's jsut assigning
> it to a controller value
> $ctrl.inventoryData = invertorydata;
> })
>
> Hope this helps you a bit,
> Regards
> Sander
>
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