while executing the code alert("promiseC done") is displaying first and
then alert("promiseC"); is displaying last because of this the data was not
displaying properly from function Displaydata(); from below code.
1. App.controller("Ctrl", function
($scope, $http, $location, $window, $sce, $q) {
2. var promiseA = getMA(Id).then(function () {
3. alert("GOT MA data from API call");
4. // doing some stuff with MA data ...
5. }
6. var promiseB = getMB(Id).then(function () {
7. alert("GOT MB data from API call");
8. // doing some stuff with MBdata ...
9. }
10. var promiseC = getMC(Id).then(function () {
11. alert("GOT MC data from API call");
12. // doing some stuff with MC data ...
13. getotherdata(MC.Id).then(function () {
14. . .
15. }
16. ..
17. alert("promiseC");
18. }
19. var promiseB = promiseA.then(function (result) {
20. alert("promiseA done");
21. });
22. var promiseC = promiseB.then(function (result) {
23. alert(" promiseB done");
24. });
25. var promiseD = promiseC.then(function (result) {
26. alert("promiseC done"); Displaydata();
27. });
28. }
How can i make to work properly so that alert("promiseC") will display
first and then alert("promiseC done").
Also tried in below way but same issue as above in chain promises.
1. var promiseA = function(){
2. var deferedA = $q.defer();
3. deferedA.resolve();
4. return deferedA.promise;
5. }
6. var promiseB = function(){
7. var deferedB = $q.defer();
8. deferedB.resolve();
9. return deferedB.promise;
10. }
11. var promiseC = function(){
12. var deferedC = $q.defer();
13. alert("promise c");
14. deferedC.resolve();
15. return deferedC.promise;
16. }
17. $q.all([promiseA, promiseB, promiseC]).then(function () {
18. alert("all done"); Displaydata();
19. })
20.
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