I'm aware that I can do that, and have been thinking I might try to 
implement some sort of variable to determine if I include my deploy.yml 
file. This solution would work in that code wouldn't deploy unless I 
explicitly set that variable via the command line. The problem with that is 
that code deployment would be accompanied by all of the other tasks for 
provisioning the server, which is no bueno.

On Friday, March 14, 2014 10:33:51 AM UTC-7, Michael DeHaan wrote:
>
> So the task file roles/foo/tasks/main.yml is always loaded, however this 
> pattern is common:
>
> main.yml:
>
> ----
> - include: debian.yml
>   when: "ansible_os_family == 'Debian'"
>
> - include: redhat.yml
>   when: "ansible_os_family == 'RedHat'"
>
> - include: common.yml   # all the time without conditionals.
>
> Hope this helps!
>
>
>
>
>
> On Fri, Mar 14, 2014 at 1:25 PM, James Goodhouse 
> <[email protected]<javascript:>
> > wrote:
>
>> When specifying a role to use in a playbook, is it possible to target a 
>> different file other than main.yml? I ask because I'm struggling to find 
>> the proper way to layout a playbook and role for my project.
>>
>> Currently I have roles created for common tasks like nginx, mysql, 
>> varnish, etc. I also have a role created specifically for my project. 
>> Inside that role I handle things like installing project specific things 
>> like APC, memcache, etc. These are each handled by a separate file that is 
>> included in the main.yml. I also have a file for deployment that is also 
>> included in the main.yml. However, I don't really want to have code deploy 
>> each time I provision a server.
>>
>> My thought was to create a deploy.yml file in the root and somehow 
>> include the role for the project, but just the deploy portion.
>>
>> How are people handling this with their projects?
>>  
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>
>

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