Excerpts from Dmitry Makovey's message of 2014-06-04 18:17:04 -0400:
> Winning combination turned out to be:
>
> ( groups['A']+groups['B'] ) | unique
>
> I do like how simple it looks vs
>
> ( groups['A']|union (groups['B']))| unique
Just FYI, the 'unique filter in the latter form is redundant; this
should work fine:
groups['A']|union(groups['B')
Sets, by definition, have no duplicate items.
--
Morgan
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