My preference in how to achieve this in a more ansible way, is using slurp,
and then checking the returned contents:
- name: Get /root/.bashrc
slurp:
src: /root/.bashrc
register: root_bashrc
- name: Enable bash-completion for root user
copy:
src: /etc/skel/.bashrc
dest: /root/.bashrc
remote_src: true
when: "'/etc/bash_completion' not in root_bashrc.content|b64decode"
I also replaced your command to copy the file, with the copy module, using
remote_src=true
On Sun, Feb 26, 2017 at 7:36 AM, Stéphane Klein <[email protected]>
wrote:
>
> Le vendredi 24 février 2017 22:40:05 UTC+1, Kai Stian Olstad a écrit :
>>
>> On 24. feb. 2017 21:56, Stéphane Klein wrote:
>> > Le vendredi 24 février 2017 21:26:38 UTC+1, Kai Stian Olstad a écrit :
>> >>
>> >>> Do you know a better solution?
>> >>
>> >> What I would do is put the correct .bashrc in Ansible and just use the
>> >> copy module to copy it to the host(s).
>> >>
>> >>
>> > I would like copy only if bash_completion isn't already present in
>> .bashrc
>>
>> Then you don't have much choice but go for the solution you posted.
>>
>> But to make the output nicer I would replace "ignore_errors: True"
>> with
>>
>> failed_when: False
>>
>> or
>>
>> failed_when: check_bashcompletion_enabled.rc > 1
>> changed_when: check_bashcompletion_enabled.rc == 1
>>
>>
>> What is it about your solution you don't like?
>>
>>
> Yes, thank it's better.
>
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