Hi ,
I have a playbook with the below lines .
$ cat double_check.yml
---
- name: playbook to test the status of the web
hosts: centos8-latest
tasks:
- block:
- name: Install the httpd packages
ansible.builtin.yum:
name: httpd
state: latest
- name: Enable and Start the httpd service
ansible.builtin.service:
name: httpd
state: started
enabled: true
- name: Check web site from web server
ansible.builtin.uri:
url: http://{{ ansible_fqdn }}
return_content: true
status_code: 200
register: example_webpage
failed_when: example_webpage.status != 200
rescue:
- name: Restart web server
ansible.builtin.service:
name: httpd
state: restarted
#we still can have handlers to demo this playbook
This Playbook works as expected until the status code is 200.
[user@centos8-latest html]$ ls -l
total 4
-rw-r--r-- 1 root root 104 Jul 28 10:36 index.html
[user@centos8-latest html]#
If there is no index.html , CentOS/redhat shows its apache foundation
page which is returning a different status code[409 ] . which is causing
the task to fail .
I am expecting the Status Code 200 [success] , 409[already running] and
404/others[failed]
How can we handle this error? Ignore_error=yes is not required.
If Status Code = 200 , then no change required . ( a handler to be called
after that )
if status code=409 , it should pass and still continue to next task (if
added). (no handler to be called )
other codes/404 can fail.
Is there an option to declare "status code =200 or 409 "in the single line?
Or we have to handle them with 2 different play ? possible ?
--
You received this message because you are subscribed to the Google Groups
"Ansible Project" group.
To unsubscribe from this group and stop receiving emails from it, send an email
to [email protected].
To view this discussion on the web visit
https://groups.google.com/d/msgid/ansible-project/8a3da674-b6cb-4868-ae41-9d690f7b6ca9n%40googlegroups.com.
