Thanks again for the comments. Another revision:
<project name="MyProject" default="dist" basedir=".">
<!-- set global properties for this build -->
<property name="src" value="." />
<property name="build" value="build" />
<property name="dist" value="dist" />
<target name="prepare">
<!-- Create the time stamp -->
<tstamp/>
<!-- Create the build directory structure used by compile -->
<mkdir dir="${build}" />
</target>
<target name="compile" depends="prepare">
<!-- Compile the java code from ${src} into ${build} -->
<javac srcdir="${src}" destdir="${build}" />
</target>
<target name="dist" depends="compile">
<!-- Create the ${dist}/lib directory
put everything in ${build} into the MyProject-${DSTAMP}.jar file-->
<mkdir dir="${dist}/lib" />
<jar jarfile="${dist}/lib/MyProject-${DSTAMP}.jar"
basedir="${build}" />
</target>
<target name="clean">
<!-- Delete the ${build} and ${dist} directory trees -->
<deltree dir="${build}" />
<deltree dir="${dist}" />
</target>
</project>
------------------------------
Changes this time:
Hey Barrie... It's still grey!
Changed the name of the project from "foo" to "MyProject." Is there a way
to get the project name as a property?
Removed init target and put tstamp into prepare.
Removed the comment in the file about filtering
Removed the <include> tags (after downloading last night's build).
Decided not to add a javadoc target. I want to keep this really simple.
Barrie, perhaps one of us should update the javadoc example after this
one.
Decided to leave ${src} as "." I'm in the "build.xml is part of the source
code" school. And I want kids at home to be able to toss this file into a
directory with some java source and get a .jar file.
Dave
