Based on the current grammar, this rule is not a set:
NUMBER : '0'..'9'
| 'A'..'Z'
| '_'
;
But the following is not:
NUMBER : '0'..'9'
| 'A'..'Z'
| ('_')
;
By modifying testBlockAsSet, testSetElement, and testSetRule to return
[int numAlts], you can keep track of more allowable sets, including
those that have a fragment rule as an element. Grammar.isValidSet() then
returns true if no exception is thrown and the returned number of alts
is greater than 1.
Sam
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