At 17:24 25/11/2009, David-Sarah Hopwood wrote:
>Jim Idle wrote:
>> expr : ae+=andExpr (OR ae+=andExpr)* -> ^(OR $ae+) ;
>
>That isn't what the poster asked for: it will produce '(OR a)'
>when the input is an andExpr, whereas what I posted above
>should produce just 'a', if I haven't made a mistake.
I think the += based equivalent is this:
expr
: (andExpr -> andExpr)
((OR ae+=andExpr)+ -> ^(OR $expr $ae+))?
;
A fair bit harder to read, although it can be expanded to do
weirder things a bit easier. :)
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