Hi,
I'm trying to troubleshoot why an input is matching to a lexer rule
instead of a dot pattern in the parser and could use some help. The
grammar is being used to interpret user-entered searches, and the idea
is that a search surrounded by double quotes should be interpreted
as-is. The dot pattern I'm using has worked for everything I have come
across so far, until someone pointed this search out to me:
"3/4 Abstract w/Talent"
The AST tree I'm given back by this is a " node with (Abstract w /
Talent), as if the "3/4" part were never entered. If I get rid of my
DATE lexer rule and associated parser rules, it works fine.
Here is a snippet of the parser rules:
negationSearch
: ('-'^)? (quotedSearch | dateRangeSearch | comparisonSearch |
idSearch | wildcardSearch | term)
;
wildcardSearch
: TEXT_WITH_WILDCARD -> ^(WILDCARD TEXT_WITH_WILDCARD)
;
idSearch
: '#'^ TEXT
;
comparisonSearch
: '>'^ TEXT
| '<'^ TEXT
;
quotedSearch
: // within double quotes, output whitespace to default channel
(don't ignore whitespace, in other words)
{ ((SwitchingCommonTokenStream)input).setTokenTypeChannel(
WHITESPACE, Token.DEFAULT_CHANNEL ); }
'"'^
.+ // non-greedy by default
{ ((SwitchingCommonTokenStream)input).setTokenTypeChannel(
WHITESPACE, Token.HIDDEN_CHANNEL ); }
'"'!
;
dateRangeSearch
: '[' DATE TO DATE ']' -> ^(DATE_BETWEEN DATE+)
| '[' AFTER DATE ']' -> ^(DATE_AFTER DATE)
| '[' BEFORE DATE ']' -> ^(DATE_BEFORE DATE)
;
subSearch
: '('! orSearch ')'!
;
term : SEPARATOR* (t=anyText -> $t)
(SEPARATOR t2=anyText -> ^(AND $term $t2))*
SEPARATOR*
;
anyText : (TO | AFTER | BEFORE | DATE | TEXT)
;
The related lexer rules look like this:
fragment NUM
: ('0'..'9') ;
DATE : ('0'..'1')? NUM '/' ('0'..'3')? NUM '/' NUM NUM NUM NUM ;
I would expect the dot in quotedSearch to match to "3/4", rather than
the DATE lexer rule matching to it, since I am already inside the
double quotes. Is there something I might be able to do to fix this?
(I'm using antlr 3.1.2.)
Thanks,
Ben
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