Hi Michael,
I have great news for you. ANTLR does this for you. Here's an example:
//
// Parser rules
statement: pos | neg ;
pos: ID 'is' ID ;
neg: 'not' ID ;
//
// Lexer rules
ID: ('A'..'Z' | 'a'..'z')+ ;
This example works because ANTLR tests tokens produced by ID against
literal values used in the parser. Try it out.
Cheers
./m
Michael Moore wrote:
> Hi guys,
>
>
>
> This is probably a bit of a newbie question, but I'm trying to write a rule
> that basically says "match any 'foo' that also does not match any 'bar'"
> where 'foo' is a basic rule (matches all letters and numbers) and 'bar' is a
> list of keywords. Is there a way to produce this kind of logic in ANTLR or
> does the logic need to be approached from a different direction to solve
> this one?
>
>
>
> Thanks,
>
> Mike
>
>
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