> Tree Grammar Output = {vs{vs} }
What's happening is that you are essentially synthesizing a complex string
template
containing multiple <v>'s. This gets evaluated eventually in main(),
which is why you see {vs {vs}}. Instead, force the substitution
before returning a new template. So your tree grammar will look like this:
tree grammar blockTree;
options {
language = Java;
output = template;
tokenVocab = block;
ASTLabelType = CommonTree;
}
@header {
// package tg_bug;
}
rule: ^(BLOCK (vstring += v)* (sstring+=s)* ENDBLOCK) ->
template(a={$BLOCK.text}, v={$vstring}, s={$sstring},
b={$ENDBLOCK.text})
<< <a><v><s><b> >>
;
v: 'v' -> template() "v";
s: 's' -> template() "s"
| x=rule ->
template(r={$x.st.toString()})
<< <r> >>
;
(I took the liberty to change the style of the template spec for "s", and I
commented out
the 'package tg_bug' decl's to get this thing to compile and run for me.
Packages-sigh.)
The key change is the template spec for the production "s->rule". The
"toString()" forces the
evaluation of the s.t. before creating a new one.
> However if I re-write the grammar as below, I don't have this problem.
>
> b->'{' '}'
> | '{' v '}'
> | '{' s '}'
> | '{' v+ s+ '}'
Not sure which grammar you're referring to b/c there is a parse grammar and
a tree grammar. Don't do this. That's not the problem, and it looks ugly.
> RTFM
Reading never really helps. Always better to just debug the friggin' code
and figure
out what it is doing.
Ken
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