On 3/20/11 1:11 PM, "Matt Fowles" <[email protected]> wrote:
Hi Matt,
> Ruslan,
> Try:
>
> query_expression
> : query_term (( "union" | "except" )^ "all"? query_term)*
> -> ^(QUERY_EXPRESSION $query_expression)
> ;
Well, $ not helps. Still same
error 165 uses rewrite syntax and also an ast operator
As I understand,
-> is re-write syntax
^ is AST operator ...
> Matt
>
> On Sun, Mar 20, 2011 at 10:40 AM, Ruslan Zasukhin
> <[email protected]> wrote:
>> Hi All,
>>
>> In v2 grammar we have rule as
>>
>> ===========================================
>> query_expression
>> : query_term (( "union"^ | "except"^ ) ( "all" )? query_term)*
>> { ## = #([QUERY_EXPRESSION,"QUERY_EXPRESSION"], ##); }
>> ;
>> ===========================================
>>
>>
>> We try change it to v3
>>
>> ===========================================
>> query_expression
>> : query_term (( "union"^ | "except"^ ) ( "all" )? query_term)*
>> ->(QUERY_EXPRESSION ???? )
>> ;
>> ===========================================
>>
>> Ops, we cannot specify top node, because it can be union OR except.
>>
>>
>> For now the only way we have found is:
>> ===========================================
>> query_expression
>> : query_expression2 ->(QUERY_EXPRESSION query_expression2)
>> ;
>>
>>
>> query_expression2
>> : query_term (( "union"^ | "except"^ ) ( "all" )? query_term)*
>> ;
>> ===========================================
>>
>>
>>
>> Question is. May be exists more elegant way for v3
>> Without additional rule?
--
Best regards,
Ruslan Zasukhin
VP Engineering and New Technology
Paradigma Software, Inc
Valentina - Joining Worlds of Information
http://www.paradigmasoft.com
[I feel the need: the need for speed]
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