I'm using the C# 3 port of Antlr (target and code generator) and I'm
experiencing a lack of lexer errors being generated. As a concrete example,
consider the following grammar:
grammar CSTest;
public
compilation_unit
: IDENTIFIER* EOF
;
IDENTIFIER
: (ID_PART) (ID_PART_OR_NUMBER)*
;
fragment
ID_PART
: ('a'..'z' | 'A'..'Z' | '_')
;
fragment
ID_PART_OR_NUMBER
: ID_PART
| '0'..'9'
;
WS
: (' '|'\r'|'\t'|'\n') { /*Skip();*/ $channel=Hidden; }
;
The only production in this grammar should allow for an arbitrary sequence
of identifiers, and it does. However, it also accepts ALL input, including
binary files and anything else I pipe into it. Is the default in the C#
target to silently ignore any lexing errors? In my driver program, I am not
seeing any throw exceptions when I call the compilation_unit rule.
using System;
using System.IO;
using Antlr.Runtime;
namespace CSTest {
public class Program {
public static void Main(string[] args) {
string filename;
filename = args[0];
if(!Path.IsPathRooted(filename)) {
filename = Path.Combine(Environment.CurrentDirectory, filename);
}
ICharStream input = new ANTLRFileStream(filename);
CSTestLexer lexer = new CSTestLexer(input);
CommonTokenStream tokens = new CommonTokenStream(lexer);
CSTestParser parser = new CSTestParser(tokens);
try {
parser.compilation_unit();
}
catch(RecognitionException re) {
Console.Out.WriteLine("EXCEPTION");
Console.Out.WriteLine(re.StackTrace);
}
}
}
}
--
Thanks,
Justin Holewinski
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