[Tizen Application-dev] help Required.

[Subho Dey]

Hi, 

I want open a external url from Tizen Web APP,

I used this code snippet

var appControl = new tizen.ApplicationControl("http://tizen.org/appcontrol/operation/view",

"http://www.google.com", null, null, null);

        tizen.application.launchAppControl(appControl, null, function()

            {

                console.log("launch application control succeed");

            },

            function(e) {

                console.log("launch application control failed. reason:" + e.message);

            },

            null

        );

 and added  <tizen:privilege name="http://tizen.org/privilege/application.launch"/> in the config.xml. 

In console i am getting this"launch application control failed. reason:given package is not found". As a result it is not opening the url.

Any suggestion what might be wrong?

Thanks & Regards
Subho Dey
System Engineer
Tata Consultancy Services
Building 1B,Ecospace
Plot -  IIF/12 ,New Town, Rajarhat,
Kolkata - 700156,West Bengal
India
Cell:- 9804290536
Mailto: subho....@tcs.com
Website: http://www.tcs.com
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