Richard Menedetter wrote:
>
> Hi
>
> Clarence Verge <[EMAIL PROTECTED]> wrote:
>
> CV> Baud (short for baudot) has nothing to do with the modem.
> CV> The normal teletype baud rate is (was) 110 baud. (No modem)
>
> You are wrong baud != bit/sec
Not at this point. Wait a sec. <G>
While the reciprocal of the baud rate is the bit PERIOD, it does not follow
that there is any FIXED connection between the bit period and the data rate
- unless you take the unusual position that start and stop bits are data !
Having designed UARTS I know exactly what I'm talking about in this area.
At 9600 BAUD the bit period is 104 microseconds. A byte of DATA consisting
of 8x104uSec intervals could be transmitted in 833uSec and there could be
1200 bytes transmitted per second at 9600 BAUD if nobody had to care about
start and stop bits.
So, whenever we talk of BAUD the start and stop bits must be considered.
At least that's what I always do.
I see where there is an element of confusion here, and I am certainly guilty
of adding to the confusion by using phrases like 33.6Kbaud and such like
when I should be reporting 33.6k bits/sec. I'm afraid that's just a habit
I got into due to my harware experience. I certainly apologize for this :(
But, this ONLY holds true for the MODEM transmit/receive rates due to the
higher level of encoding. The 57,600 and 115,200 SERIAL rates that your
computer uses to talk to your modem (if it is EXTERNAL) are BAUD rates
and DO contain the start and stop bits. <G>
Divide by 10 here to get bytes/sec.
Do NOT divide the modem 33600 by 10. I was definitely wrong there.
Sorry.
- Clarence Verge
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