Thank you for your responce.  After several more hours of playing around I 
got it working using     
^.*(?=.{8,})(?=.*[a-z])(?=.*[A-Z])(?=.*[^A-Za-z0-9]).*$
_____________________________________________________________________________________
 


John Atherly  |   APC by Schneider Electric   |  Information, Process & 
Organization (IPO)  |   Remedy Administrator / Developer 
Phone: +401-789-5735 ext. 2120  |   Fax: +401-789-3710  |   
Email: john.athe...@apcc.com  |   Site: www.apc.com/  |   Address: 132 
Fairgrounds Road, West Kingston, RI 02892 USA 
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LJ LongWing <lj.longw...@gmail.com> 
Sent by: "Action Request System discussion list(ARSList)" 
<arslist@ARSLIST.ORG>
03/07/2011 04:57 PM
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Subject
Re: Password pattern matching in Kinetics






** 
John,
I don’t have direct experience with Kinetic, but I would imagine you would 
need to do 3 separate checks.  By doing it the way you are, as you 
described you are saying that it must be in the order you specify.  If 
however you check it for lower, then for upper, then for special, all 3 
should pass regardless of order.
 
From: Action Request System discussion list(ARSList) 
[mailto:arslist@ARSLIST.ORG] On Behalf Of John Atherly
Sent: Monday, March 07, 2011 11:31 AM
To: arslist@ARSLIST.ORG
Subject: Password pattern matching in Kinetics
 
** 
I'm trying to create a field in Kinetics that the user will enter in the 
new password in and I want to make sure it meets the specs.  It must 
include an upper case character, a lower case character, a special 
character (for example: #, !, +, %) and be 8 characters in length. 
I've gotten it to meet the upper and lower case and the special character 
as long as it is typed in that order any thing else fails.   


([A-Z]+[a-z]+[^A-Za-z0-9])    equal any upper case followed by a lower 
case and then a special character 
were 
([^A-Za-z0-9]+[A-Z]+[a-z])    equals the same but in a different order 
special character followed by an upper case and then lower case 

or I could use 
([A-Z]+[a-z]+[0-9]+[^A-Za-z0-9])|([^A-Za-z0-9]+[A-Z]+[a-z]+[0-9]) which 
equals either of the examples but not any that start with a lower or any 
other combination. 

I think what I'm looking for should be something like    
([A-Z])([a-z])([^A-Za-z0-9]){8} 

Thanks 
_____________________________________________________________________________________
 


John Atherly  |   APC by Schneider Electric   |  Information, Process & 
Organization (IPO)  |   Remedy Administrator / Developer 
Phone: +401-789-5735 ext. 2120  |   Fax: +401-789-3710  |   
Email: john.athe...@apcc.com  |   Site: www.apc.com/  |   Address: 132 
Fairgrounds Road, West Kingston, RI 02892 USA 
*** Please consider the environment before printing this e-mail 
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