Hi,
first, thanks all for your preceding answers, it really helped me.
I've got an other question about tags without automatic tagging.
I don't understand that in X.680 28.8, the choice type B must not have
an extension marker to consider its tags as part of A (in the following
example).
In examples of 48.8, it's done and in 48.8.4, it's written that
extensible choices inside extensible choices can be constructed.
A::= SET {
b B,
c C
}
B ::= CHOICE {
d [0] NULL,
e [1] NULL
}
C ::= CHOICE {
f [2] NULL,
g [3] NULL,
...
}
Thanks,
G. Martin
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