No.It's not correct.
For,
maxBitRate ::= INTEGER(0..4294967295) ,
Let the value to be encoded is 4294967290.
Then the encoding will be ,
L:11 P:00 0000 C:1111 1111 1111 1111 1111 1111 1111 1010
L:11
The number of bits needed to represent the number of bytes that the max.
value in the range will accomodate,with an offset one(always).
So,while decoding the length should be taken as 4.
P:00 0000
Length is octet-aligned.
C:1111 1111 1111 1111 1111 1111 1111 1010
Encoding of the value 4294967290
Raam S.
-----Original Message-----
From: Patel, Avinkumar V (Avinkumar) [mailto:[EMAIL PROTECTED]]
Sent: Friday, October 20, 2000 2:01 AM
To: '[EMAIL PROTECTED]'
Subject: RE: [ASN.1] how to decode large integer type
L: 00000100 C: FFFFE9DF(it's in HEX,)
-----Original Message-----
From: Bing Zhang [mailto:[EMAIL PROTECTED]]
Sent: Thursday, October 19, 2000 10:54 AM
To: [EMAIL PROTECTED]
Subject: [ASN.1] how to decode large integer type
Would anyone tell me how to encode a large integer number(Aligened variant,
PER), for instance
maxBitRate ::= INTEGER(0..4294967295)
Thanks,
bing
