Hi,
    I need some clarification of PER encoding of constrained whole number. The ITU-T spec X.691 section 10.5 explains that for ALIGNED mode, when the range is exactly 256, the value would be encoded in one octet and it would be octet aligned. 256 is a 9 bit value, so how is it encoded in one octet. Supposing that its somehow encoded in one octet, if the generated bit stream is not octet aligned but say taking up 2.1 bytes(decimal representing the bits) then after encoding of the value would it totally use 4 bytes? Kindly advice. Thanking you.
 
Yours Sincerely
Ramaswamy

"Any intelligent fool can make things bigger, more complex, and more violent. It takes a touch of genius -- and a lot of courage -- to move in the opposite direction." - Albert Einstein

Information contained and transmitted by this E-MAIL is proprietary to
Synergy Infotech Private Limited and is intended for use only by the
individual or entity to which it is addressed, and may contain information
that is privileged, confidential or exempt from disclosure under applicable
law. If this is a forwarded message, the content of this E-MAIL may not have
been sent with the authority of the Company. If you are not the intended
recipient, an agent of the intended recipient or a  person responsible for
delivering the information to the named recipient,  you are notified that any
use, distribution, transmission, printing, copying or dissemination of this
information in any way or in any manner is strictly prohibited. We have taken
precautions to minimize the risk of transmitting software viruses, but we
advise you to carry out your own virus checks on any attachment to this
message. We cannot accept liability for any loss or damage caused by software
viruses. If you have received this communication in error, please delete this
mail & notify us immediately at mailto:[EMAIL PROTECTED]

Reply via email to