Richard Curtis wrote:
Following is a post which I hope will clarify what I have been doing up
until now, along with some questions regarding the correct way to do this.
Until now, I have always handled file uploads in the following way :
draw in HTML "<input type="file" name="filename">".
Then the form posts in on itself, and I use
my $newFile = $Request->Form('filename');
$newFile is then passed to a module which will basically do the
following (along with a lot more):
while ($rets=read($newFile,$line,1024)) { # Read in BINARY
my @lin = $line;
my $status = append_file($destination_path, $file,\@lin);
if (!$status) {
return(0,"error storing file on server ($!)");
}
@lin = ();
}
This has always worked for me.
Now however, I need to not only upload the file to the server, but I
need to store the filename in a database (among doing other things with
the filename).
When you say filename, I will assume you mean the file name client side
being uploaded...
So should I be doing :
my $newFile = $Request->{FileUpload}{filename};
$newFile = $newFile->{BrowserFile};
Right BrowserFile will give you the name of the file as it was uploaded.
?
If not, what should I be doing.
What should I call to get handle, and what should I call to get the
actual filename ?
Well, what you have been doing works fine for getting the file handle,
but you can also get it from;
$Request->FileUpload('upload_file', 'FileHandle');
I am sooo confused !
Originally, the file upload interface was only available through
doing it as you do with
my $fh = $Request->Form('upload_file')
but as users needed more of the file upload info, I created the
FileUpload collection to store more of the data. Originally
MS ASP did not have any native file upload support, so I had not
API to emulate here, and had to make it up as we went.
Regards,
Josh
________________________________________________________________
Josh Chamas, Founder phone:925-552-0128
Chamas Enterprises Inc. http://www.chamas.com
NodeWorks Link Checking http://www.nodeworks.com
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