Thank you, sir. But it is my mistake. This is a php problem that i mistakenly
sent to this ASP group.
I guess working both with asp and php, and tiredness, got me mixed up.
Again, my apologies.
Charles Carroll <[EMAIL PROTECTED]> wrote:
1 - $art = mysql_one_array("SELECT * FROM ". $table ." WHERE id='". $id ."'");
maybe?
On 5/31/05, flor bamboo <[EMAIL PROTECTED]> wrote:
>
> I can't make these codes work:
>
> 1 - $art = mysql_one_array("SELECT * FROM ". $table ." WHERE id='$id'");
>
> 2 - $art = mysql_one_array("SELECT * FROM '$table' WHERE id='$id'");
>
> the $id variable works, but i can't make the $table variable work. Can you
> please show me the right code?
>
> Thanks.
>
>
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