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Hi Zusammen,
=20
auf unserer Homepage k=C3=B6nnen sich de Kunden f=C3=BCr Seminare =
anmelden,
jetzt wurde etwas am Code ver=C3=A4ndert, was ich leider nicht =
nachvollziehen
kann
, bzw. einfach nicht Verstehe wo denn der Hund begraben liegt <grmpf>
=20
nachfolgend einmal der betroffene Code:
=20
<%
dim sqlString
dim adoConn
dim adoRst
dim ConnStr
dim dbPath
dbPath =3D "../../../db/seminare.mde"
=20
ConnStr =3D "PROVIDER=3DMicrosoft.Jet.Oledb.4.0;" + _=20
"Data Source=3D" + server.MapPath(dbPath)
=20
sqlString =3D "SELECT * FROM qry_Seminare " + _
"WHERE SeminarNr =3D " + =
Cstr(Request.QueryString("SeminarNr"))
set adoConn =3D server.CreateObject("ADODB.connection")
set adoRst =3D server.CreateObject("ADODB.recordset")
=20
adoConn.Open ConnStr
adoRst.Open sqlString, adoConn <------------ Fehlermeldung =
kommt
hier
%>
=20
=20
Bei Aufruf der Seite kommt folgender Fehler:
=20
Fehler '80040e10'=20
/sites/9_Veranst/9_02_Seminare/SeminarAnmeldung.asp, line 52=20
=20
Kann mir vielleicht jemand auf die Spr=C3=BCnge helfen?
Danke + Gr=C3=BC=C3=9Fe,
Florian.
=20
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<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.0 Transitional//EN">
<HTML><HEAD>
<META HTTP-EQUIV=3D"Content-Type" CONTENT=3D"text/html; =
charset=3Dutf-8">
<META content=3D"MSHTML 5.00.3315.2870" name=3DGENERATOR></HEAD>
<BODY>
<DIV><FONT face=3DArial size=3D2><SPAN class=3D951354613-18012002>Hi=20
Zusammen,</SPAN></FONT></DIV>
<DIV><FONT face=3DArial size=3D2><SPAN=20
class=3D951354613-18012002></SPAN></FONT> </DIV>
<DIV><FONT face=3DArial size=3D2><SPAN class=3D951354613-18012002>auf =
unserer Homepage=20
k=C3=B6nnen sich de Kunden f=C3=BCr Seminare =
anmelden,</SPAN></FONT></DIV>
<DIV><FONT face=3DArial size=3D2><SPAN class=3D951354613-18012002>jetzt =
wurde etwas am=20
Code ver=C3=A4ndert, was ich leider nicht nachvollziehen =
kann</SPAN></FONT></DIV>
<DIV><FONT face=3DArial size=3D2><SPAN class=3D951354613-18012002>, =
bzw. einfach nicht=20
Verstehe wo denn der Hund begraben liegt =
<grmpf></SPAN></FONT></DIV>
<DIV><FONT face=3DArial size=3D2><SPAN=20
class=3D951354613-18012002></SPAN></FONT> </DIV>
<DIV><FONT face=3DArial size=3D2><SPAN =
class=3D951354613-18012002>nachfolgend einmal=20
der betroffene Code:</SPAN></FONT></DIV>
<DIV> </DIV>
<DIV><FONT color=3D#ff0000 face=3DArial size=3D2><SPAN=20
class=3D951354613-18012002><%<BR> dim =
sqlString<BR> dim=20
adoConn<BR> dim adoRst<BR> dim =
ConnStr<BR> dim=20
dbPath<BR> dbPath =3D "../../../db/seminare.mde"<BR> =20
<BR> ConnStr =3D "PROVIDER=3DMicrosoft.Jet.Oledb.4.0;" + _=20
<BR> "Data Source=3D" +=20
server.MapPath(dbPath)</SPAN></FONT></DIV>
<DIV> </DIV>
<DIV><FONT color=3D#ff0000 face=3DArial size=3D2><SPAN=20
class=3D951354613-18012002> sqlString =3D "SELECT * FROM =
qry_Seminare " +=20
_<BR> "WHERE SeminarNr =
=3D " +=20
Cstr(Request.QueryString("SeminarNr"))<BR> set adoConn =3D=20
server.CreateObject("ADODB.connection")<BR> set adoRst =3D=20
server.CreateObject("ADODB.recordset")<BR> <BR> ad=
oConn.Open=20
ConnStr<BR> <FONT color=3D#0000ff>adoRst.Open sqlString,=20
adoConn <-=
-----------=20
Fehlermeldung kommt hier<BR> </FONT>%></SPAN></FONT></DIV>
<DIV><FONT color=3D#ff0000 face=3DArial size=3D2><SPAN=20
class=3D951354613-18012002></SPAN></FONT> </DIV>
<DIV><FONT color=3D#ff0000 face=3DArial size=3D2><SPAN=20
class=3D951354613-18012002></SPAN></FONT> </DIV>
<DIV><FONT face=3DArial size=3D2><SPAN class=3D951354613-18012002>Bei =
Aufruf der Seite=20
kommt folgender Fehler:</SPAN></FONT></DIV>
<DIV><FONT color=3D#0000ff face=3DArial size=3D2><SPAN=20
class=3D951354613-18012002></SPAN></FONT> </DIV>
<DIV><FONT color=3D#000000 face=3DArial size=3D2><SPAN =
class=3D951354613-18012002><FONT=20
color=3D#0000ff><FONT face=3DArial size=3D2>Fehler '80040e10'</FONT> =
</FONT>
<P><FONT color=3D#0000ff><FONT face=3DArial=20
size=3D2>/sites/9_Veranst/9_02_Seminare/SeminarAnmeldung.asp</FONT><FONT=
=20
face=3DArial size=3D2>, line 52</FONT> </FONT></P></SPAN></FONT></DIV>
<P><FONT face=3DArial size=3D2><SPAN=20
class=3D951354613-18012002></SPAN></FONT> </P>
<P><FONT face=3DArial size=3D2><SPAN class=3D951354613-18012002>Kann =
mir vielleicht=20
jemand auf die Spr=C3=BCnge helfen?</SPAN></FONT></P>
<P><FONT face=3DArial size=3D2><SPAN class=3D951354613-18012002>Danke + =
Gr=C3=BC=C3=9Fe,</SPAN></FONT></P>
<P><FONT face=3DArial size=3D2><SPAN=20
class=3D951354613-18012002>Florian.</SPAN></FONT><FONT =
size=3D2></P></FONT>
<DIV> </DIV>
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