yes, i'm not sure how i would detect?
i don't know the syntax to say if sender = literal, do this, or if
sender = textbox, do this. do you know raj? thanks!
public void OnDataBinding(object sender, EventArgs e)
{
Literal lc = (Literal) sender;
--- In [EMAIL PROTECTED], "Rajendra Appalla"
<[EMAIL PROTECTED]> wrote:
> Then may be you can check for the sender type whether it's a label
or a
> text box.
> If it's a textbox, then write code appropriate to that.
> May be this will work. Hard part would be trying to find out
whether
> it's a label or a textbox.
>
> Please let me know after you try it or find a solution to this
issue.
> Thanks.
>
> Raj.
>
> -----Original Message-----
> From: Trevor Thompson [mailto:[EMAIL PROTECTED]
> Sent: Monday, July 26, 2004 5:00 PM
> To: [EMAIL PROTECTED]
> Subject: [AspNetAnyQuestionIsOk] Re: help w/ dynamically created
> datagrid
>
> that doesnt work b/c as you can see in my OnDataBinding function
> below, it is assigning the 'incoming' control as a literal. and
when
> it's not a literal, it bombs.
>
> --- In [EMAIL PROTECTED], "Rajendra Appalla"
> <[EMAIL PROTECTED]> wrote:
> > You need to check for the Item Type in the InstantiateIn method
of
> your
> > class.
> >
> > Also I forgot to tell you that you need to add the following line
> in the
> > case of EditItem after adding the textbox to the container
similar
> to
> > lbl in the ItemType of Item.
> >
> > txt.DataBinding += new EventHandler(OnDataBinding);
> >
> > Hope this works.
> >
> > I did not try it.
> >
> > Raj.
> >
> > -----Original Message-----
> > From: Rajendra Appalla
> > Sent: Monday, July 26, 2004 4:42 PM
> > To: [EMAIL PROTECTED]
> > Subject: RE: [AspNetAnyQuestionIsOk] Re: help w/ dynamically
created
> > datagrid
> > Importance: High
> >
> > See this code.
> >
> > public void InstantiateIn(System.Web.UI.Control container)
> > {
> > Label lbl = new Label();
> > switch(templateType)
> > {
> > case ListItemType.Header:
> > lbl.Text = strTableLabel;
> > container.Controls.Add(lbl);
> > break;
> > case ListItemType.Item:
> > lbl.Text = strColumnName;
> > container.Controls.Add(lbl);
> > lbl.DataBinding += new
> > EventHandler(OnDataBinding);
> > break;
> > case ListItemType.EditItem:
> > TextBox txt = new TextBox();
> > txt.Text = strColumnName;
> > container.Controls.Add(txt);
> > break;
> > case ListItemType.Footer:
> > lbl.Text = "<I>" + strColumnName
> + "</I>";
> > container.Controls.Add(lbl);
> > break;
> > }
> > }
> >
> > Raj.
> >
> > -----Original Message-----
> > From: Trevor Thompson [mailto:[EMAIL PROTECTED]
> > Sent: Monday, July 26, 2004 4:44 PM
> > To: [EMAIL PROTECTED]
> > Subject: [AspNetAnyQuestionIsOk] Re: help w/ dynamically created
> > datagrid
> >
> > well it's not really 'convoluted'. i needed a way in which i
could
> > dynamically add template columns. i cannot have auto-generated
> > columns. also, the example does not show anything about my
original
> > question in regards to having my data show up in a textbox. i
need
> to
> > figure out how to have my data show up in a textbox. thanks!
> >
> > --- In [EMAIL PROTECTED], "Charles M.
Carroll"
> > <[EMAIL PROTECTED]> wrote:
> > > well that is sort of a convoluted way ....
> > >
> > > look at:
> > > http://www.learnasp.com/freebook/learn/cs_xmltodataset.aspx
> > > to see less convoluted example of dynamically creating
DataGrids.
> > >
> > >
> > > At 03:26 PM 7/26/2004, you wrote:
> > >
> > > >i'm having a heck of a time with my new dynamically created
> > datagrid.
> > > >anyone willing to help out?
> > > >
> > > >i have figured out how to dynamically create a datagrid that
> > > >populates with the data that i pass through to my template
column
> > > >using code on microsoft and dotnetbips. but now i need to
figure
> > out
> > > >how to make this displayed data show up inside of a textbox.
> please
> > > >see my working code below that takes inputted column name and
> > creates
> > > >a datagrid with the value from that column in my dataset
showing
> up
> > > >in the datagrid. now i just need to add a textbox with that
> value.
> > > >
> > > >public class DataGridTemplate : ITemplate
> > > >
> > > >{
> > > > ListItemType templateType;
> > > > string columnName;
> > > >
> > > > public DataGridTemplate(ListItemType type, string colname)
> > > > {
> > > > templateType = type;
> > > > columnName = colname;
> > > > }
> > > >
> > > > public void OnDataBinding(object sender, EventArgs e)
> > > > {
> > > > Literal lc = (Literal) sender;
> > > > DataGridItem container = (DataGridItem) lc.NamingContainer;
> > > > lc.Text = ((DataRowView)container.DataItem)
> > [columnName].ToString();
> > > > }
> > > >
> > > > public void InstantiateIn(System.Web.UI.Control container)
> > > > {
> > > > Literal lc = new Literal();
> > > > lc.DataBinding += new EventHandler(this.OnDataBinding);
> > > > container.Controls.Add(lc);
> > > > }
> > > >}
> > > >
> > > >
> > > >
> > > >public class edit_version_datagrid : System.Web.UI.UserControl
> > > >{
> > > > beginning class code here...
> > > >
> > > > //dynamically add datagrid code
> > > > TemplateColumn tc1 = new TemplateColumn();
> > > > tc1.ItemTemplate = new
> > > > DataGridTemplate(ListItemType.Item, "proj_fy");
> > > > datagrid2.Columns.Add(tc1);
> > > > Page.Controls[1].Controls.Add(datagrid2);
> > > > datagrid2.DataSource = MyView;
> > > > datagrid2.DataBind();
> > > >
> > > >}
> > > >
> > > >
> > > >
> > > >
> > > >
> > > >
> > > >Yahoo! Groups Links
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