ok try 5 :) ----- Original Message ----- From: "Tony Trapp" <[EMAIL PROTECTED]> To: <[email protected]> Sent: Thursday, May 12, 2005 12:27 AM Subject: Re: [AspNetAnyQuestionIsOk] VB.net String maniplulation problem
> Ok I dim x as integer > > now I get back an error: > > > Server Error in '/' Application. > -------------------------------------------------------------------------------- > > Input string was not in a correct format. > Description: An unhandled exception occurred during the execution of the > current web request. Please review the stack trace for more information > about the error and where it originated in the code. > > Exception Details: System.FormatException: Input string was not in a > correct format. > > Source Error: > > Line 330: newstring_withnum_tostr = words1.substring(location + x, > 1) > Line 331: > Line 332: words1.Replace(newstring_withnum_tostr, > Cint(newstring_withnum_tostr) + 1) > Line 333: > Line 334: ' newstr = words1.Insert(newstring_withnum_tostr + 4, "_" & > Counter + 1) > > ----- Original Message ----- > From: Mischa Kroon > To: [email protected] > Sent: Wednesday, May 11, 2005 3:02 PM > Subject: Re: [AspNetAnyQuestionIsOk] VB.net String maniplulation problem > > > x stands for I'm not certain at this point :) > I think it's 5 > but could be 4 > > Pizza sounds good btw :) > > > > ----- Original Message ----- > From: "Tony Trapp" <[EMAIL PROTECTED]> > To: <[email protected]> > Sent: Thursday, May 12, 2005 12:11 AM > Subject: Re: [AspNetAnyQuestionIsOk] VB.net String maniplulation problem > > > > Micha fallowing along I know x in math represents the unknown and of > > course if its not declared I will get back an error so what is x > > representing in this equation? > > > > Thanks for your help by the way, can I buy you a pizza? LOL > > > > Tony... > > > > ----- Original Message ----- > > From: Mischa Kroon > > To: [email protected] > > Sent: Wednesday, May 11, 2005 2:48 PM > > Subject: Re: [AspNetAnyQuestionIsOk] VB.net String maniplulation > problem > > > > > > whoops didn't read the full message. > > > > here is where you go wrong i think :) > > > > > > > location = words1.IndexOf("_new") > > > > > > If location > 0 or not -1 then > > > > > > > location will give the location of the start of "_new" > > you want the next char not the position of the "_" > > > > then: newstring_withnum_tostr = words1.substr (location + x, 1) > > words1.replace (newstring_withnum_tostr, cint > (newstring_withnum_tostr) + > > 1 ) > > > > check it: > > > > response.write (words1) > > > > > > > > > > > > ----- Original Message ----- > > From: "Tony Trapp" <[EMAIL PROTECTED]> > > To: <[email protected]> > > Sent: Wednesday, May 11, 2005 11:13 PM > > Subject: [AspNetAnyQuestionIsOk] VB.net String maniplulation problem > > > > > > > Hey guys here is what I want to do. > > > > > > Lets say I have a file name is my database my_pic_new1.jpg first > off. > > > > > > Now I want to change this file name to make it a uniqe file name but > > > I need to do a few things to the string first. > > > > > > Is in the string _new is there then I want to see if a number is > > > there. > > > > > > If there is a number there I want to take that number and what ever > > > it is increment that number up by one make the file now > > > my_pic_new2.jpg > > > > > > and so on. > > > > > > I am not asking for someone to write the code for me but point me to > > > where I can gain viable info on how to make this hapeen or a small > > > code example. > > > > > > Here is my code at present, > > > > > > > > > Dim words1 as String = tmnescort_currentpic_small > > > > > > Dim location as Integer > > > Dim Counter as Integer > > > Dim newstr as Integer > > > Dim newstring_withnum as Integer > > > Dim countvar as Integer > > > Dim newstring_withnum_tostr > > > dim addnum as String > > > > > > Counter = 0 > > > location = words1.IndexOf("_new") > > > > > > If location > 0 or not -1 then > > > > > > newstring_withnum_tostr = instr(1, words1, "1") > > > > > > > > > newstr = System.Convert.ToInt16 > > > (newstring_withnum_tostr + 1) > > > newstring_withnum = newstr & Counter + 1 > > > addnum = System.Convert.ToString(newstring_withnum) > > > > > > str_msg.Visible = True > > > str_msg.Text = "This is the pic name in DB " & > > > tmnescort_currentpic_small & "<br><br>new string was found<br><br>" > & > > > addnum & "<br><br>" > > > > > > else > > > > > > str_msg.Visible = True > > > str_msg.Text = "This is the pic name in DB " & > > > tmnescort_currentpic_small & "<br>new string was not found<br><br>" > & > > > addnum & "<br><br>" > > > > > > end if > > > > > > > > > what I get back printed out is > > > > > > This is the pic name in DB my_pic_new1.jpg > > > > > > new string was found > > > > > > 161 << this is what happens after my string manipualtion I dont want > > > this. > > > > > > Can any please help me? > > > > > > Thanks, > > > > > > Tony... > > > > > > > > > > > > > > > > > > > > > Yahoo! Groups Links > > > > > > > > > > > > > > > > > > > > > > > > -- > > > No virus found in this incoming message. > > > Checked by AVG Anti-Virus. > > > Version: 7.0.308 / Virus Database: 266.11.8 - Release Date: > 5/10/2005 > > > > > > > > > > > > > > > ------------------------------------------------------------------------------ > > Yahoo! Groups Links > > > > a.. To visit your group on the web, go to: > > http://groups.yahoo.com/group/AspNetAnyQuestionIsOk/ > > > > b.. To unsubscribe from this group, send an email to: > > [EMAIL PROTECTED] > > > > c.. Your use of Yahoo! Groups is subject to the Yahoo! Terms of > > Service. > > > > > > > > [Non-text portions of this message have been removed] > > > > > > > > > > Yahoo! Groups Links > > > > > > > > > > > > > > > > -- > > No virus found in this incoming message. > > Checked by AVG Anti-Virus. > > Version: 7.0.308 / Virus Database: 266.11.8 - Release Date: 5/10/2005 > > > > > > > > ------------------------------------------------------------------------------ > Yahoo! Groups Links > > a.. To visit your group on the web, go to: > http://groups.yahoo.com/group/AspNetAnyQuestionIsOk/ > > b.. To unsubscribe from this group, send an email to: > [EMAIL PROTECTED] > > c.. Your use of Yahoo! Groups is subject to the Yahoo! Terms of > Service. > > > > [Non-text portions of this message have been removed] > > > > > Yahoo! Groups Links > > > > > > > > -- > No virus found in this incoming message. > Checked by AVG Anti-Virus. > Version: 7.0.308 / Virus Database: 266.11.8 - Release Date: 5/10/2005 > Yahoo! Groups Links <*> To visit your group on the web, go to: http://groups.yahoo.com/group/AspNetAnyQuestionIsOk/ <*> To unsubscribe from this group, send an email to: [EMAIL PROTECTED] <*> Your use of Yahoo! Groups is subject to: http://docs.yahoo.com/info/terms/
