Thanks Dean.
That does the trick.
For anyone else who needs this function, here it is:

    Function MD5Encrypt(ByVal str As String) As String

        Dim md5 As 
System.Security.Cryptography.MD5CryptoServiceProvider
        Dim bytValue() As Byte
        Dim bytHash() As Byte
        Dim strOutput As String
        Dim i As Integer

        ' Create New Crypto Service Provider Object
        md5 = New 
System.Security.Cryptography.MD5CryptoServiceProvider

        ' Convert the original string to array of Bytes
        bytValue = System.Text.Encoding.UTF8.GetBytes(str)

        ' Compute the Hash, returns an array of Bytes
        bytHash = md5.ComputeHash(bytValue)
        md5.Clear()

        For i = 0 To bytHash.Length - 1
            'don't lose the leading 0
            strOutput &= bytHash(i).ToString("x").PadLeft(2, "0")
        Next

        MD5Encrypt = strOutput

        ' 11111111 = 1bbd886460827015e5d605ed44252251 in mysql
        ' 11111111 = 1bbd886460827015e5d605ed44252251 in VB.Net
        ' G72IZGCCcBXl1gXtRCUiUQ== UTF8
        

    End Function

--- In [email protected], Dean Fiala 
<[EMAIL PROTECTED]> wrote:
> If you take a look at the output you'll see that mySQL is 
returning 32
> hexadecimal characters.
> 
> You'll see the ComputeHash function is returning 16 bytes, the 
base64
> is converting it into 24 characters that are not limited to
> hexadecimal range. But if you convert a byte into its hexidecimal
> representation, you get 2 hexadecimal chars 16x2 = 32 j(don't 
forget
> to keep the leading 0s.)
> 
> So what you need to do is convert each byte in bytHash to its
> hexadecimal representation.
> 
> There is a probably a simplr way to this, but its late.
> 
>         Dim i As Integer
>         For i = 0 To bytHash.Length - 1
>             'don't lose the leading 0
>             strOutput &= bytHash(i).ToString("x").PadLeft(2, "0")
>         Next
> 
> 
> 





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