Fantastic.  This looks to be the level of brilliance I was looking for - 
simplicity plus 100% solution.

So follow-up question.  I have a lot of advanced math in grad school, all 
inapplicable to this.  Is there any kind of measure of how "random" a set of 
numbers is?  Someone internal is bound to ask.  I am thinking of graphing the 
difference [=n(i+1)-n(i)] and looking at distribution.  The client(s) are 
business persons and are unlikely to ask.

Question 2:  I have a passion for documenting things.  Do you wish to have your 
name attached to this idea?

Tomorrow when I have time I will peruse all the answers.

Profound thanks

Peace be w/y'all

-----Original Message-----
From: IBM Mainframe Assembler List [mailto:[email protected]] On 
Behalf Of Farley, Peter x23353
Sent: Tuesday, May 16, 2017 4:51 PM
To: [email protected]
Subject: Re: random quest

1.      Use either CEERAN0 or FUNCTION RANDOM to generate a column of 99,999 
random numbers.  It's OK if there are duplicates.
2.      Add a second column using SORT with sequential numbers from 1 to 99999 
(use the SEQNUM option). 
3.      SORT by the first column only and DO NOT specify the EQUALS option.
4.      Use the numbers in column 2 after sorting as your 99,999 randomly 
ordered numbers

You can combine steps 2, 3, and 4 in one SORT execution.  INREC to add the 
SEQNUM's as a second column, SORT by first column, OUTREC to select only the 
second column for output.

HTH

Peter

-----Original Message-----
From: IBM Mainframe Assembler List [mailto:[email protected]] On 
Behalf Of Richard Kuebbing
Sent: Tuesday, May 16, 2017 4:28 PM
To: [email protected]
Subject: random quest

So I need a set of 99,999 random numbers which are 5 digits and unique, i.e. no 
duplicates.  CEERAN0 and Cobol FUNCTION RANDOM both give sets w/30+% duplicates.

I have seen website random.org.

Anyone have to ever done this thing?

Anyone have suggestions?

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