No, &DISP doesn't have to be a SETC symbol and there's no need to make a copy
of &CTR3. Of course, the code would be more readable if you chose better names
for the variables than &CTR*.
Try putting a period at the end of the name
ST R14,&CTR3.(R1)
--
Shmuel (Seymour J.) Metz
http://mason.gmu.edu/~smetz3
________________________________________
From: IBM Mainframe Assembler List [[email protected]] on behalf
of Joe Reichman [[email protected]]
Sent: Sunday, March 22, 2020 10:56 AM
To: [email protected]
Subject: Help building a parameter list
Hi
I have a macro which takes a variable number of parameters as parameters
to a called program best I give any example
CALLPGM &PGM,&PARMLST,&PARM1..&PARMC
LCLA &CTR1,&CTR2,&CTR3
LCLC &DISP
&CTR1 SETA N'&SYSLIST
&CTR2 SETA 3
&CTR3 SETA 0
LA R1,&PARMLST
.LOOP ANOP
AIF (&CTR2 EQ CTR1).SETEND
.*
.* I Think the displacement has to be a SETC symbol not a SETA
.*
&DISP SETC '&CTR3'
LA R14,&SYSLIST(&CTR3)
ST R14,&DISP(R1)
&CTR1 SETA &CTR1+1
&CTR3 SETA &CTR3+4
AGO .LOOP
I am getting the following assembler error "ST R14,&DISP(R1)"
** ASMA108E Inconsistent dimension on SET symbol reference; default=0, null,
or Whether I was the above syntax
Or ST R14,&CTR3(R1)
Any guidance appreciated
thanks
