Generally speaking, for most instructions and architectures, comparisons end at inequality, to unequal operands may compare faster than equal ones.
Charles -----Original Message----- From: IBM Mainframe Assembler List [mailto:[email protected]] On Behalf Of Bob Flanders Sent: Wednesday, June 7, 2023 11:28 AM To: [email protected] Subject: Re: Shower thought So does that mean if I compare two long byte vectors where the first byte is x'80' in the first operand, and the second is x'00' in the second operand, the operation is the fastest it can be? (It would take much longer if the two strings are completely equal?) -- Bob Flanders I Cor 15:1-4 > <Kersnip />
