cc: [email protected]
Subject: Re: [ast-developers] typeset in signal trap ==> compound array
contains typeset statements
--------
> Can anyone explain why the following code contains FOUR array elements
> instead of two? I'm getting desperate with this. I only want to
> declare c.car[index].int as a integer variable (aka typeset -li) but
> receive this garbage instead when running it with ast-ksh.20130807:
>
> ksh -c 'set -o nounset ; compound c ; compound -a c.car; integer
> c.cari=0; trap "typeset -i c.car[c.cari++].int=\${.sh.sig.value.int}"
> RTMIN RTMAX ; kill -q4 -s RTMIN $$ ; true ; kill -q17 -s RTMAX $$ ;
> true ; print -v c'
> (
> typeset -C -a car=(
> [0]=(
> int=4
> )
> [1]=(
> typeset -i int=0
> )
> [2]=(
> int=17
> )
> [3]=(
> typeset -i int=0
> )
> )
> typeset -l -i cari=4
> )
>
> Ced
> --
> Cedric Blancher <[email protected]>
> Institute Pasteur
>
I can explain why it is happening, but I haven't decided how to resolve it.
typeset foo=bar
is parsed as if it is
foo=bar typeset foo
However since you have
typeset foo[i++]=bar
this becomes
foo[i++]=bar typeset foo[i++]
Your workaround is to do
typeset -i c.car
before the trap and do
trap "tc.car[c.cari++].int=\${.sh.sig.value.int}"
for the trap.
David Korn
[email protected]
_______________________________________________
ast-developers mailing list
[email protected]
http://lists.research.att.com/mailman/listinfo/ast-developers
