On 16 August 2013 07:18, Roland Mainz <[email protected]> wrote:
> On Fri, Aug 16, 2013 at 6:42 AM, Roland Mainz <[email protected]>
> wrote:
>> On Fri, Aug 16, 2013 at 12:45 AM, David Korn <[email protected]> wrote:
>>> cc: [email protected]
>>> Subject: Re: Re: [ast-developers] AT&T Software Technology ast alpha
>>> software download update
>>> --------
>>>
>>>> ksh tst1.sh
>>>> tst1.sh: line 3: .sh.type.com.gelifesciences.tst1: no parent
>>>>
>>>> Irek
>>>
>>> Try this patch and see if it fixed the types problem in namespaces.
>>> =====================cut here======================
>>> --- old/sh/xec.c Mon Aug 12 13:22:06 2013
>>> +++ new/sh/xec.c Thu Aug 15 18:01:37 2013
>> [snip]
>>> =====================cut here======================
>>
>> The patch seems to fix half the problems. The types can now be defined
>> but a variable declared with such a type can't find it's type
>> functions:
>> -- snip --
>> $ ksh -o nounset -c 'namespace a.b.c { typeset -T x_t=( integer i=5 )
>> ; function pi { printf "i=%d\n" $((_.i+_.i)) ; } ; } ; .a.b.c.x_t var
>> ; var.pi'
>> /bin/ksh: var.pi: not found
>> -- snip --
>> AFAIK this should print "10" ...
>
> ... and it does... if I would've put the ')' at the right place:
> -- snip --
> $ ksh -o nounset -c 'namespace a.b.c { typeset -T x_t=( integer i=5 ;
> function pi { printf "i=%d\n" $((_.i+_.i)) ; } ) ; } ; .a.b.c.x_t var
> ; var.pi'
> i=10
> -- snip --
>
> Sorry for the mess... |ENOCOFFEE| ... ;-(
> ... the patch works... thanks... :-)
>
Arithmetic expressions still don't work in namespaces:
ksh -c 'namespace a1.a2 { integer n=2 ; print $((i+i)) ; }'
0
It should print '4'.
Ced
--
Cedric Blancher <[email protected]>
Institute Pasteur
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