The arithmetic function int() does not work in sh (AT&T Research) 93v- 2013-08-27
I get this: ksh -c 'print -- $(( log2( int(pow(2,69) )) ))' 69 But it should print 'nan', as it does if I use explicitly an intermediate integer variable: ksh -c 'integer i; print -- $(( i=pow(2,69) , log2(i) ))' nan Tina -- Tina Harriott - Women in Mathematics Contact: [email protected] _______________________________________________ ast-developers mailing list [email protected] http://lists.research.att.com/mailman/listinfo/ast-developers
