The following function behaves somewhat peculiar:
function f
{
ksh --version # 1993-12-28 s+
typeset p t
p=f
typeset +f $p # OK
t=$(typeset +f $p)
print "$t" # ?? empty
set -- f
typeset +f $1 # OK
t=$(typeset +f $1)
print "$t" # OK
}
The crucial part is the assignment 't=$(typeset +f $X)'. If X is a normal
name, and $X is "f", the result is empty. If X is 1, and $1 is "f", the
result is whatever 'typeset +f f' outputs.
Looks like a bug to me. Or are normal variables and positional parameters
supposed to behave different in this context?
Regards,
Bernd
--
Bernd Eggink
[EMAIL PROTECTED]
http://sudrala.de
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