David, how can I test if a array is entirely made out of compound
variables or type variables, i.e. is one of:
compound -a array
compound -A array
typeset -T a_t=(...) ; a_t -a array
typeset -T a_t=(...) ; a_t -A array
I tried this code:
...
array_np = nv_open("array", shp->var_tree,
NV_VARNAME|NV_NOFAIL|NV_NOADD);
...
if (!nv_isattr(array_np, NV_COMVAR))
{
puts("nv_isattr(array_np, NV_COMVAR) failed.");
}
if (!nv_isvtree(array_np))
{
puts("nv_isvtree(array_np) failed.");
}
...
The code will print this in all 4 cases:
nv_isattr(array_np, NV_COMVAR) failed.
nv_isvtree(array_np) failed.
Which leaves me confused, how I can test if the array is entirely made
out of compound variables or type variables.
Olga
--
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{ \/`o;====- Olga Kryzhanovska -====;o`\/ }
.----'-/`-/ olga.kryzhanov...@gmail.com \-`\-'----.
`'-..-| / http://twitter.com/fleyta \ |-..-'`
/\/\ Solaris/BSD//C/C++ programmer /\/\
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